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3 years ago

Simplify (10 + 3i)(5 – 2i) ...?

Mathematics

2 answers:

iogann1982 [59]3 years ago

6 0

(10+3i)(5-2i)
30i=50-20i
50i=50
i=1

maybe

Fiesta28 [93]3 years ago

3 0

Answer:

$56-5i$

Step-by-step explanation:

Given are two complex numbers

10+3i and 5-2i

We are to find its product

Let us use foil method to multiply these two binomials.

$(10+3i)(5-2i)\\=50+15i-20i-6i^2\\$

Use the fact that i square =-1

We get product

= $50-5i+6\\=56-5i$

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Step-by-step explanation:

You can use FOIL to do this. First terms, Outer terms, Inner terms, Last terms.

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Outer terms: x * 2 = 2x

Inner terms: -3 * 4x = -12x

Last terms: -3 * 2 = -6

Now add these together:

4x^2 + 2x - 12x - 6 = 4x^2 - 10x - 6

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David, Egil and Frances share money in the ratio 2:7:9. Frances gets ?80 more than David. Explain how you know Egil gets ?80.

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Step-by-step explanation:

We have been given that David, Egil and Frances share money in the ratio 2:7:9.

Let 2x, 7x and 9x be the amounts of money that David, Agil and Frances get respectively.

We are told that Frances gets $80 more than David. So we can write this information in an equation as:

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Now let us solve for x.

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Now let us substitute $x=\frac{80}{7}$ in 7x (amount of money that Egil gets).

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