I hope this helps you
let's find AB
AB=square root of 2^2+3^2
AB=square root of 13
cosO=2/sqrt13
sinO=3/sqrt13
tgO=3/2
ctgO=2/3
Answer:
Value of x = -1 and y = -4
Step-by-step explanation:
BC = 3 (given)
BC = AD ( opposite sides of a parallelogram are equal)
∴ AD = 3
AD = x - y (given)
∴ 3 = x - y
3 + y = x -------- (1)
CD = 2 (given)
CD = AB (opposite sides of a parallelogram are equal)
∴ AB = 2
AB = 2x - y (given)
∴ 2 = 2x - y ----------- (2)
Putting the value of x in (1) To (2)
2 = 2(3+y) - y
2 = 6 + 2y - y
2 = 6 + y
2 - 6 = y
-4 = y
Now, substitute the value of y in (1)
x = 3 + y
x = 3 + (-4)
x = 3 - 4
x = -1
Therefore, the value of x = -1 and y = -4.
<u>Cross-checking</u>
2x - y = 2
2*-1 - (-4) = 2
-2 -(-4) = 2
-2 + 4 = 2
2 = 2
LHS = RHS
x - y = 3
-1 -(-4) = 3
-1+4 = 3
3 = 3
LHS = RHS
Thus verified
Hope u understand
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