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2 years ago

Write the equation y=3/4x+4 in standard form

Mathematics

1 answer:

LenKa [72]2 years ago

3 0

Answer:

3x-4y=-16

Step-by-step explanation:

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An exponential function f(x) is reflected across the x-axis to create the function g(x). Which is a true statement regarding f(x

valentina_108 [34]

That would be the last choice. Opposite meaning different sign

4 0

3 years ago

Read 2 more answers

Simplify 3+7x-(2+9x)

viva [34]

Answer:

-2x + 1

Step-by-step explanation:

3 + 7x - (2 + 9x)

Distribute the negative:

3 + 7x - 2 - 9x

Combine like terms:

-2x + 1

8 0

2 years ago

–0.4(3x – 2) + StartFraction 2 x plus 4 Over 3 EndFraction for x = 4

Nadusha1986 [10]

Answer:

Step-by-step explanation:

Given

- 0.4(3x - 2) + $\frac{2x+4}{3}$ ← substitute x = 4 into the expression

= - 0.4(3(4) - 2) + $\frac{2(4)+4}{3}$

= - 0.4(12 - 2) + $\frac{8+4}{3}$

= - 0.4(10) + $\frac{12}{3}$

= - 4 + 4 = 0

4 0

2 years ago

Read 2 more answers

Evaluate the integral ∫2−1|x−1|dx

defon

I think you might be referring to the definite integral,

$\displaystyle \int_{-1}^2|x-1|\,\mathrm dx$

Recall the definition of absolute value:

$|x| = \begin{cases}x&\text{if }x\ge0\\-x&\text{if }x$

Then $|x-1|=x-1$ if $x\ge1$ , and $|x-1|=1-x$ is $x$ . So spliting up the integral at <em>x</em> = 1, we have

$\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \int_{-1}^1(1-x)\,\mathrm dx + \int_1^2(x-1)\,\mathrm dx$

The rest is simple:

$\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \left(x-\dfrac{x^2}2\right)\bigg|_{-1}^1 + \left(\dfrac{x^2}2-x\right)\bigg|_1^2 \\\\ = \left(\left(1-\frac12\right)-\left(-1-\frac12\right)\right) + \left(\left(2-2\right)-\left(\frac12-1\right)\right) \\\\ = \boxed{\frac52}$

5 0

2 years ago

Can somebody help and explain too me cause I don’t understand please

bearhunter [10]

is the answer for this question -4 + 8x

7 0

2 years ago