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Monica [59]
3 years ago
11

Write the equation y=3/4x+4 in standard form

Mathematics
1 answer:
LenKa [72]3 years ago
3 0

Answer:

3x-4y=-16

Step-by-step explanation:

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Pls send proper answer , urgent
Rina8888 [55]
Answer: B

Explanation:

Equation of line y=mx+b

m = y2-y1/x2-x1 = 2-(-2)/1-(-1) = 4/2 = 2

b = (0,0)

y = 2x+0

y=2x
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sammy [17]
Fifth term / second term = a1r^4 / a1r = r^3 = 768 / -12 = -64

so r = -4  and first term a1 =  -12/-4 = 3  

answer is  3*(-4)^(n-1)

Its C
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4 years ago
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5/6 is a rational number
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4 years ago
Find the point P on the line yequals=33x that is closest to the point (60 comma 0 )(60,0). What is the least distance between P
scoray [572]

Answer:

18\sqrt{10}$ units

Step-by-step explanation:

We are given the equation of the line y=3x and a point, say Q(60,0) outside of that line.

We want to find the point on the line y=3x which is closest to Q.

Let P(x,y) be the desired point. Since it is on the line y=3x, it must satisfy the line.

If x=a, y=3a, so the point P has the coordinates (a,3a).

Distance between point Q and P

=\sqrt{(60-a)^2+(0-3a)^2}\\D =\sqrt{10a^2-120a+3600}

To minimize D, we find its derivative

\dfrac{dD}{da}=\dfrac{10a-60}{\sqrt{10a^2-120a+3600} }\\$Setting \dfrac{dD}{da}=0\\10a-60=0\\10a=60\\a=6

Therefore, the y-coordinate for P is 3*6=18.

The point P=(6,18).

Next, we calculate the distance between P(6,18) and (60,0).

D =\sqrt{10(6)^2-120(6)+3600}\\=\sqrt{3240}\\=18\sqrt{10}$ units

8 0
4 years ago
Perform the operation x-y/2 - x+y/3
slega [8]

Answer:

First one

Step-by-step explanation:

x-5y/6

7 0
3 years ago
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