What is the slope of the line?

Mathematics

1 answer:

vodomira [7]2 years ago

8 0

Answer:

The slope of the line is 1 I think

Step-by-step explanation:

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Pls hurry

AlladinOne [14]

Step-by-step explanation:

To evaluate, substitute 29 for the variable in the expression.

To evaluate, substitute 31 for the variable in the equation.

To evaluate the expression, add 31 to 29.

The correct expression is n-31.

To evaluate the expression, subtract 31 from 29Pls hurry

Rafael writes an expression to represent "a number, n, decreased by thirty-one." Then he evaluates that expression if

n-29. Which statements are true about the expression and its evaluation? Check all that apply.

The correct expression is 31-n.

This is a subtraction expression.

This is an addition expression.

To evaluate, substitute 29 for the variable in the expression.

To evaluate, substitute 31 for the variable in the equation.

To evaluate the expression, add 31 to 29.

The correct expression is n-31.

To evaluate the expression, subtract 31 from 29..

4 0

2 years ago

Read 2 more answers

Factor 2pq - 5qr + 10r - 4p.

Tresset [83]

The answer is B) <span>(q - 2)(2p - 5r)

</span>2pq - 5qr + 10r - 4p = 2pq - 4p - 5qr + 10r
= 2pq - 4p - (5qr - 10r)
= 2p(q - 2) - 5r(q - 2)
= (q - 2)(2p - 5r)

5 0

2 years ago

Which of the following constants can be added to x2 + x to form a perfect square trinomial?

solmaris [256]

The constant should be added to form a perfect square trinomial will be 1/4. Then the correct option is D.

<h3>What is a quadratic equation?</h3>

It's a polynomial with a value of zero. There exist polynomials of variable power 2, 1, and 0 terms. A quadratic equation is an equation with one statement in which the degree of the parameter is a maximum of 2.

The expression is x² + x.

Then the constant should be added to form a perfect square trinomial.

Then the constant will be

The square of the half of the coefficient of the variable x is to be added to make a perfect square.

Then the constant will be 1/4.

Then the perfect square will be

$\rm \rightarrow x^2 + x + \dfrac{1}{4}\\\\\\\rightarrow x^2 + 2 \times \dfrac{1}{2} x + \left (\dfrac{1}{2} \right )^2\\\\\\\rightarrow \left (x + \dfrac{1}{2} \right)^2$