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jeyben [28]
3 years ago
15

A can contain 24 fluid ounce of fruit juice. how many pints of fruit juice does the can contain?

Mathematics
1 answer:
Serga [27]3 years ago
7 0
<h2>Hello!</h2>

The answer is: 1,5 pints.

<h2>Why?</h2>

Firts, we must know that:

1 cup = 8 oz.

and:

2 cup = 1 pint

Knowing that, we can calculate how many pints of fruit juice does the can contain

If 1 cup = 8 oz. and 2 cup = 1 pint

So,

24 oz.*\frac{1 cup}{8oz.} =3 cup

We have that 24oz.= 3 cup

Then, calculating, we have:

3 cup*\frac{1 pint.}{2 cup.} = 1,5 pints.\\

So,  a can of 24 ounce of fruit juice is equal to 3 cups of fruit juice, and it's equal to 1,5 pints of fruit juice.

Have a nice day!

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Prove that (4n+1)^2(4n-1)^2 is a multiple of 8 for all integers of n.<br><br> thanks.
azamat

Answer: i think  (4n+1)^2(4n-1)^2 isnt a multiple of 8 for all integers of n because:

(4n + 1)²(4n - 1)²

= [(4n + 1)(4n - 1)]²

= (16n² - 1)²

= 16².n².n² - 2.16.n² + 1

= 8n²(32n² - 4) + 1

can see 8n²(32n² - 4) is a multiple of 8 but 1 isnt a multiple of 8

=> (4n + 1)²(4n - 1)² isnt a multiple of 8 for all integers of n.

Step-by-step explanation:

6 0
3 years ago
Find the volume of the rectangular prism with a base area of 63 and a height of 14 feet.
gayaneshka [121]

Answer:

63 = 14

devide 14 on both sides

14/14 cancels out

63/14 = 4.5

the answer is 4.5

5 0
3 years ago
Hi, I am taking PSAT and I am working on the math section. I need help with answering this math type of question. Please give th
ValentinkaMS [17]

By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)

<h3>How many more distance does the average race car travels than the average consumer car?</h3>

In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:

s' = (v' - v) · t

Where:

  • v' - Speed of the average race car, in miles per hour.
  • v - Speed of the average consumer car, in miles per hour.
  • t - Time, in hours.

Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:

s' = (210 - 120) · (30 / 3600)

s' = 3 / 4 mi

The distance surplus of the average race car is equal to 3 / 4 miles.

To learn more on uniform rectilinear motion: brainly.com/question/10153269

#SPJ1

4 0
1 year ago
∠A and \angle B∠B are supplementary angles. If m\angle A=(7x+10)^{\circ}∠A=(7x+10) ∘ and m\angle B=(7x-26)^{\circ}∠B=(7x−26) ∘ ,
blsea [12.9K]

Answer:

108 degrees

Step-by-step explanation:

Since angles A and B are supplementary, they both add up to 180. Angle A = 7x+10, and angle B = 7x-26. You can set up the equation A + B = 180, and then plug in angles A and B, which gives you 7x+10 + 7x-26 = 180. Then you just need to isolate x:

Combine like terms: 14x - 16 = 180

Add 16 to both sides: 14x = 196

Divide both sides by 14: x = 14

Now that you know x, you can plug it into the expression for angle A (7x+10):

A = 7(14) + 10 = 98+10 = 108

5 0
2 years ago
Mary throws her Grandma’s favorite crystal dish out the second floor window, which is 6 meters from the ground. She is really up
wlad13 [49]

we know that

acceleration due to gravity is 9.8m/s^2

so, we get

a(t)=9.8

and acceleration will always be constant

we know that

integral of acceleration is velocity

so, we can integrate both sides

\int \:a\left(t\right)dt=\int \:9.8dt

v(t)=9.8t+C

we are given

v(0)=35m/s

we can use it and find C

v(0)=9.8*0+C

35=9.8*0+C

C=35

now, we can plug it back

v(t)=9.8t+35

we know that

integral of velocity is height

we can integrate it again

\int \:v\left(t\right)dt=\int \:\left(9.8t+35\right)dt

s(t)=\int \:\left(9.8t+35\right)dt

s(t)=4.9t^2+35t+C

now, we have

s(0)=6

we can use it and find C

s(0)=4.9(0)^2+35(0)+C

6=4.9(0)^2+35(0)+C

now, we can plug back C

C=6

and we get

s(t)=4.9t^2+35t+6.............Answer

4 0
3 years ago
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