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2 years ago

Which equation produces a line that is parallel to the line represented by the function below? y=2/5x+9

2 answers:

6 0

Hello :

a line that is parallel to the line represented by the function below? y=2/5x+9
has same slope : 2/5
an equation is: y =( 2/5)x+b

mezya [45]2 years ago

5 0

I am assuming you meant:

y=2x/5+9

If so:

A parallel line must have the same slope. The line is of the form:

y=mx+b where m=slope, in this case 2/5

So the parallel line will be of the form:

y=2x/5+b where b is the y-intercept.

There are infinitely many solutions as any line with the same slope is parallel to the original line. However the y-intercept can be any real number, that is why there are infinitely many solutions...Any value of b in the line we found above will still be parallel to the original line...

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Answer:

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Step-by-step explanation:

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2 years ago

A jumping spider's movement is modeled by a parabola. The spider makes a single jump from the origin and reaches a maximum heigh

Stella [2.4K]

A parabola is a mirror-symmetrical U-shape.

The equation of the parabola is $\mathbf{y = -\frac{1}{640}(x - 80)^2 + 10}$
The focus is $\mathbf{Focus = (80, -1760)}$
The directrix is $\mathbf{y = \frac{1}{640}}$
The axis of the symmetry of parabola is: $\mathbf{x = 80}$

From the question, we have:

$\mathbf{Vertex: (h,k) = (80,10)}$

$\mathbf{Origin: (x,y) = (0,0)}$

The equation of a parabola is:

$\mathbf{y = a(x - h)^2 + k}$

Substitute the values of origin and vertex in $\mathbf{y = a(x - h)^2 + k}$

$\mathbf{0 = a(0 - 80)^2 + 10}$

$\mathbf{0 = a(- 80)^2 + 10}$

$\mathbf{0 = 6400a + 10}$

Collect like terms

$\mathbf{6400a =- 10}$

Solve for a

$\mathbf{a =- \frac{1}{640}}$

Substitute the values of a and the vertex in $\mathbf{y = a(x - h)^2 + k}$

$\mathbf{y = -\frac{1}{640}(x - 80)^2 + 10}$

The focus of a parabola is:

$\mathbf{Focus = (h, \frac{k+1}{4a})}$

Substitute the values of a and the vertex in $\mathbf{Focus = (h, \frac{k+1}{4a})}$

$\mathbf{Focus = (80, \frac{10+1}{4 \times -\frac{1}{640}})}$

$\mathbf{Focus = (80, -\frac{11}{\frac{1}{160}})}$

$\mathbf{Focus = (80, -11\times 160)}$

$\mathbf{Focus = (80, -1760)}$

The equation of the directrix is:

$\mathbf{y = -a}$

So, we have:

$\mathbf{y = \frac{1}{640}}$ ----- the directrix

The axis of symmetry is:

$\mathbf{x = -\frac{b}{2a}}$

We have:

$\mathbf{y = -\frac{1}{640}(x - 80)^2 + 10}$

Expand

$\mathbf{y = -\frac{1}{640}(x^2 -160x + 6400) +10}$

Expand

$\mathbf{y = -\frac{1}{640}x^2 +\frac{1}{4}x - 10 +10}$

$\mathbf{y = -\frac{1}{640}x^2 +\frac{1}{4}x }$

A quadratic function is represented as:

$\mathbf{y = ax^2 + bx + c}$

So, we have:

$\mathbf{a = -\frac{1}{640}}$

$\mathbf{b = \frac{1}{4}}$

Recall that:

$\mathbf{x = -\frac{b}{2a}}$

So, we have:

$\mathbf{x = -\frac{1/4}{2 \times -1/640}}$

$\mathbf{x = \frac{1/4}{1/320}}$

This gives

$\mathbf{x = \frac{320}{4}}$

$\mathbf{x = 80}$

Hence, the axis of the symmetry of parabola is: $\mathbf{x = 80}$

Read more about parabola at:

brainly.com/question/21685473

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2 years ago

Pls help with this question

kirill115 [55]

Answer: first answer choice

Step-by-step explanation:

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2 years ago

Laila made 12 muffins. Shannon made 10 muffins how many more did Laila make?

sleet_krkn [62]

Answer:

2 more muffins

Step-by-step explanation:

Since,

Given that:

Laila made 12 Muffins

Shannon made 10 Muffins

Question to Answer:
How many more did Laila make?

Solve:

Since it asking how many more laila made that means we have to subtract to find how many more laila has.

As given, we know that Laila made 12 Muffins and Shannon made 10 Muffins then:

Laila Muffins - Shannon Muffins

Which also means:

12 - 10

Which,

12 - 10 = 2

Hence, Laila makes 2 more Muffins than Shannon

Kavinsky

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1 year ago

Read 2 more answers

Two lines intersect to form a linear pair with equal measures. One angle had the measure 2x and the other angle had the measure

rosijanka [135]

Answer:

x = 45, y = 5

Step-by-step explanation:

It is given that two lines form a linear pair with equal measures. Therefore, the angle between the two lines will be 90. Now, according to the question,

2x + 20y - 10 =90

2x+20y = 100

x + 10y = 50

And

2x = 20y-10

x = 10y -5

x - 10 y = -5

Now, adding x + 10y = 50 and x - 10y =-5, the value of x can be found. The required value will be:

x + 10y =50

x - 10y = -5

------------------

x = 45

Therefore, the value of y after substitution of the value of x in one of the equations will be:

90 = 20y - 10

20 y = 100

y = 5

Hence, the required value of x and y are 45 and 5 respectively.

4 0

2 years ago