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mote1985 [20]
3 years ago
12

Write equation for the line that is perpendicular to the y axis and passing through (5,1)

Mathematics
1 answer:
Alla [95]3 years ago
3 0

Answer:

Step-by-step explanation:

A line perpendicular to the y-axis, which is vertical, is a line that is horizontal. Perfectly horizontal lines always have a slope of 0. Thus, the equation of the line perpendicular to the one given and passing through the given point (5, 1) is

y - 1 = 0(x - 5) and

y - 1 = 0x - 0 and

y - 1 = 0 so

y = 1 is the equation you're looking for.

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I need help pls help
Snezhnost [94]

Answer:

c.

Step-by-step explanation:

hope this helps

3 0
3 years ago
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12.<br> What is the<br> equation of a circle with center (-7, -3) and radius 2?
Genrish500 [490]

Answer:

(x + 7)^2 + (y + 3)^2 = 4

Step-by-step explanation:

The standard equation of a circle is:

(x - h)^2 + (y - k)^2 = r^2

where (h, k) is the center and r is the radius. We can substitute the information given to obtain:

(x + 7)^2 + (y + 3)^2 = 4

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3 years ago
Examine the pattern in the powers of i you wrote in the table, and create a rule for finding the value of large powers of i. Jus
denpristay [2]
Let N be any integer. Then

i^N=\begin{cases}1&\text{if }N\equiv0\mod4\\i&\text{if }N\equiv1\mod4\\-1&\text{if }N\equiv2\mod4\\-i&\text{if }N\equiv3\mod4\end{cases}

In other words:

(1) If N is a multiple of 4, then i^N=1.

(2) If dividing N by 4 leaves a remainder of 1, then i^N=i, since i^N=i^{4n+1} for some integer n, and from (1) we know that i^{4n+1}=i^{4n}i=i (because, obviously, 4n is a multiple of 4).

(3) If instead you get a remainder of 2, then i^N=-1. This follows from (1) as well. i^N=i^{4n+2}=i^{4n}i^2=(1)(-1)=-1.

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5 0
3 years ago
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mylen [45]

Answer:

Step-by-step explanation:

5x + 12 = 12x + 5

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one solution

8 0
3 years ago
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Harrizon [31]

Answer:

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x = -9

7 0
3 years ago
Read 2 more answers
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