7 - 5 x m
-4 x 3
i believe these are correct if this isnt is there any other information?
Answer:
≈ -5.1857
≈ -5.4857
≈ 3.7262
Step-by-step explanation:
Rewrite the equation system as:
Now, write the system in its augmented matrix form:
![\left[\begin{array}{cccc}6&8&0&-75\\-3&6&6&5\\2&-9&0&39\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D6%268%260%26-75%5C%5C-3%266%266%265%5C%5C2%26-9%260%2639%5Cend%7Barray%7D%5Cright%5D)
applying row reduction process to its associated augmented matrix:
Swap R1 and R3, and then Swap R1 and R2:
![\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\6&8&0&-75\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-3%266%266%265%5C%5C2%26-9%260%2639%5C%5C6%268%260%26-75%5Cend%7Barray%7D%5Cright%5D)
R3+2R1
![\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\0&20&12&-65\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-3%266%266%265%5C%5C2%26-9%260%2639%5C%5C0%2620%2612%26-65%5Cend%7Barray%7D%5Cright%5D)
3R2+2R1
![\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&20&12&-65\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-3%266%266%265%5C%5C0%26-15%2612%26127%5C%5C0%2620%2612%26-65%5Cend%7Barray%7D%5Cright%5D)
15R3+20R2
![\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&0&420&1565\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-3%266%266%265%5C%5C0%26-15%2612%26127%5C%5C0%260%26420%261565%5Cend%7Barray%7D%5Cright%5D)
Now we have a simplified system:
From (3):
(4)
Replacing (4) in (2)
(5)
Finally replacing (5) and (4) in (1)
Easy
differnce of 2 perfect squares
a²-b²=(a+b)(a-b)
in this case
x⁴=(x²)²
16=4²
(x²)²-4²=(x²+4)(x²-4)
x²-4 can be factored since 4=2²
x²-2²=(x+2)(x-2)
complete factored form is
(x²+4)(x+2)(x-2)
gegroup to seperate (x+2)
(x+2)[(x²+4)(x-2)]
(x+2)p(x)
p(x)=(x²+4)(x-2)
expanded
p(x)=x³-2x²+4x-8
Answer:
Step-by-step explanation:
Let the number of dimes be d and quarters be q
<u>The value is $8.80 = 880¢, so:</u>
- 10d + 25q = 880 ⇒ 2d + 5q = 176
<u>If the dimes were quarters and the quarters were dimes, the coins' total value would be $7.30 or 730¢</u>
- 25d + 10q = 730 ⇒ 5d + 2q = 146
<u>Now we have 2 equations. Solving the system by elimination, subtract 5 times the second equation from twice the first equation:</u>
- 2(2d + 5q) - 5(5d + 2q) = 2(176) - 5(146)
- 4d - 25d = -378
- -21d = -378
- d = -378/-21
- d = 18
0.45
90/2=45% chance they will go 110/2=55% chance they won't go
