Answer: The answer is AB = CD.
Step-by-step explanation: We are given a quadrilateral ABCD with AB ║ CD.
We know that a quadrilateral is said to be a parallelogram if any one of the following conditions is satisfied:
(i) If both pairs of opposite angles of a quadrilateral are equal, then it is a parallelogram.
(ii) If one pair of opposite sides of a quadrilateral is both equal and parallel, then it is a parallelogram.
(iii) If the diagonals of a quadrilateral bisect each other, then it is a parallelogram.
We are given that AB is parallel to CD, so by the condition (ii), if we get the additional information that AB = CD, then ABCD will be a parallelogram.
Thus, the answer is AB = CD.
Answer:
This is proved by ASA congruent rule.
Step-by-step explanation:
Given KLMN is a parallelogram, and that the bisectors of ∠K and ∠L meet at A. we have to prove that A is equidistant from LM and KN i.e we have to prove that AP=AQ
we know that the diagonals of parallelogram bisect each other therefore the the bisectors of ∠K and ∠L must be the diagonals.
In ΔAPN and ΔAQL
∠PNA=∠ALQ (∵alternate angles)
AN=AL (∵diagonals of parallelogram bisect each other)
∠PAN=∠LAQ (∵vertically opposite angles)
∴ By ASA rule ΔAPN ≅ ΔAQL
Hence, by CPCT i.e Corresponding parts of congruent triangles PA=AQ
Hence, A is equidistant from LM and KN.
If one inch equals 25.4 millimeters, you would have to divide 25.4 by 1/8 which equals to 3.2 (3.175 before rounding). Subtract 3.2 from 25.4 = 22.2 millimeters