Find an equation of a line that has intercepts (1,0) and (0,4)
2 answers:
Slope = (4-0)/(0-1) = -4
b = 4
equation
y = -4x + 4
(1,0),(0,4)
slope = (4 - 0) / (0 - 1) = -4/1 = -4
the y int is when x = 0.....so ur point (0,4) tells us that the y int is 4
in y = mx + b form, the slope will be in the m position and the y int will be in the b position
y = mx + b
slope(m) = -4
y int (b) = 4
sub
y = -4x + 4 <== or 4x + y = 4....depending on what form u need it in
You might be interested in
Answer:
The diagonal is about 14 m
Step-by-step explanation:
A = s^2
98 = s^2
so
s = √98
diagonal c^2 = 98 + 98
c^2 = 196
c = √196
c ≈ 14
Answer:
The diagonal is about 14 m
Q = 3s - 9/6
q = 3(s - 3)/6
q = s - 3/2
6q + 9 = 3s
6q + 9/3 = s
3(2q + 3)/3 = s
2q + 3 = s
s = 2q + 3
Answer:
Step-by-step explanation:
4x + 3y = 24
4x - y = 8
4x + 3y = 24
-4x + y = -8
4y = 16
y = 4
4x - 4 = 8
4x = 12
x = 3
(3, 4)
Answer:
y<-6 and y>10
Step-by-step explanation:
