Given a = {1, 3, 5}, b = {2, 4, 6} and c={1, 2, 3, 4, 5, 6}, then a ∪ (b ∩ <br>
c. =
Afina-wow [57]
A ∪ (b ∩ c) = {1, 3, 5} ∪ {2, 4, 6} = {1, 2, 3, 4, 5, 6} = c
Answer:
See Below.
Step-by-step explanation:
We want to verify the identity:

Note that the left-hand side is a perfect square trinomial pattern. Namely:

If we let <em>a</em> = csc(x) and <em>b</em> = cot(x), we can factor it as such:

Let csc(x) = 1 / sin(x) and cot(x) = cos(x) / sin(x):

Combine fractions:

Square (but do not simplify yet):

Now, we can make a substitution. Let <em>u</em> = <em>x</em> / 2. So, <em>x</em> = 2<em>u</em>. Substitute:

Recall that cos(2u) = 1 - sin²(u). Hence:

Simplify:

Recall that sin(2u) = 2sin(u)cos(u). Hence:

Square:

Cancel:

Since sin(u) / cos(u) = tan(u):

We can substitute <em>u</em> back for <em>x</em> / 2:

Hence proven.
Hello,
Let's calculate the radius:
r²=5²+7²=74
The circle's equation is (x+5)²+(y+7)²=74
Answer C
Answer:
see attachment
Step-by-step explanation:
Answer:
fourth one
Step-by-step explanation: