Because all numbers that are divisible by 10 is divisible by 5, all numbers that are divisible by 8 is divisible by 2 and 4, all numbers divisible by 6 is divisible by 2 and 3, we only need to find the smallest common multiple of 6,7,8,9,10 and 11
find the prime factors of each:
2,3
7
2,2,2,
3,3,
2,5,
11
factors that are shared can be used only once, so we have:
2*7*3*11*3*2*5*2=27720
SOLUTION: the sum of two numbers is 25 and their difference is 15. what are the two numbers? let x =one number and y= the other number. the corresponding modeling system is {x+y=25 x-y=
6)
-4
-1
2
5
8
7) each time the x column goes up 1, the fx column goes up 3
These are the only ones i know. Sorry i cant be more helpful :(
I. -7/10
K. 675/1000 or 27/40
M. -26/100
O. 5 55/100 the 5 by itself is a whole number
J 84/100 or 21/25
L -252/1000
N 2 78/100
p 11 688/100
Y = 3x² - 9x + 12
y' = 6x - 9 = 0
6x = 9
x = 9/6 = 3/2
