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3 years ago

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Peter has 3 fewer baseball cards than twice the number of Pokemon cards he owns. If b represents the number of baseball cards Pe

ter has, write an expression that represents the total number of baseball cards and pokemon cards that Peter owns.

1 answer:

oee [108]3 years ago

7 0

Answer:

2x - 3 = b

Step-by-step explanation:

x is the no. of pokemon cards

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Answer:

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Step-by-step explanation:

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3 years ago

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Q.1. Base and height if a parallelogram 12 cm and 8 cm respectively. Find its area.

irakobra [83]

Answer:

Area of the parallelogram is 96 $cm^{2}$ .

Step-by-step explanation:

A parallelogram is a quadrilateral with parallel and equal length of opposite sides. The diagonals are perpendicular to each other.

Area of a parallelogram is given as,

Area = base x height

Thus for the given parallelogram with base 12 cm and height 8 cm, the area would be;

Area = base x height

= 12 x 8

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Area = 96 $cm^{2}$

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3 years ago

you are attempting to guess a 3 digit number and have the following information. there are no 0s the number is even. the sum of

ss7ja [257]

The 3-digit number is 132

<h3>How to determine the 3-digit number?</h3>

The given parameters are:

Number of digits = 3
Sum of digits = 6
No 0s in the number
No repeated digit

The first highlight above implies that the number can be any of 100 to 999

The other highlights imply that the no digit can appear repeatedly, the highest digit in the number is 3, and the number must end with 2.

So, we have:

X32

The first digit is the smallest.

1 is smaller than 3 and 2.

So, we have

132

Hence, the 3-digit number is 132

Read more about digits and numbers at:

brainly.com/question/26856218

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2 years ago

Where is the constant on here?<br><br> 12+ x - 3.7 - 8y + 1/3

SCORPION-xisa [38]

12-3.7+(1/3)=constant
259/30=constant

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3 years ago

Would appreciate the help !

aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

$\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 2

$\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 3

$\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\$

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity $\sin^2(\theta)+\cos^2(\theta) = 1$ in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

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2 years ago