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umka2103 [35]
2 years ago
11

If R is the midpoint of OS , RS = 2x - 4, ST = 4x – 1, and RT = 8x – 43, find QS.

Mathematics
1 answer:
RoseWind [281]2 years ago
5 0

Answer:

56

Step-by-step explanation:

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Hi please help me answer this!!
just olya [345]

The numbers that are irrational are B. √72 and D.√23.

<h3>What are irrational numbers?</h3>

Irrational numbers are those that have infinite numbers after the decimal. These numbers are also none repeating.

When the above are solved:

√25 = 5

√144 = 12

√23 = 4.79583152331...

√72 = 8.48528137424...

The only two numbers with non-repeating and infinite numbers are √72 and √23.

Find out more on irrational numbers at brainly.com/question/20400557

#SPJ1

7 0
1 year ago
Mrs. Laura is between 50 and 80. If you divide her age by 9, the remainder is 1. If you divide by 4, the remainder is 1. How old
Mila [183]

Answer:

73 y/o

Step-by-step explanation:

Multiples of 9   between 50 and 80:

54    63     72     now add 1

55    64     73     now divide by 4 to find which has remainder of 1

73 y/o

3 0
1 year ago
Read 2 more answers
Does anyone know why I only got 2/3 marks, and can you explain how to get 3 marks please. Please answer.
Brums [2.3K]

Answer:

294cm²

Step-by-step explanation:

You didn’t convert from meters to centimeters.

It was 2.94m².

That equals 294cm².

5 0
2 years ago
Given f of x is equal to 1 over the quantity x minus 3 end quantity and g of x is equal to the square root of the quantity x plu
Lostsunrise [7]

The domain of the composite function is given as follows:

[–3, 6) ∪ (6, ∞)

<h3>What is the composite function of f(x) and g(x)?</h3>

The composite function of f(x) and g(x) is given as follows:

(f \circ g)(x) = f(g(x))

In this problem, the functions are:

  • f(x) = \frac{1}{x - 3}.
  • g(x) = \sqrt{x + 3}

The composite function is of the given functions f(x) and g(x) is:

f(g(x)) = f(\sqrt{x + 3}) = \frac{1}{\sqrt{x + 3} - 3}

The square root has to be non-negative, hence the restriction relative to the square root is found as follows:

x + 3 \geq 0

x \geq -3

The denominator cannot be zero, hence the restriction relative to the denominator is found as follows:

\sqrt{x + 3} - 3 \neq 0

\sqrt{x + 3} \neq 3

(\sqrt{x + 3})^2 \neq 3^2

x + 3 \neq 9

x \neq 6

Hence, from the restrictions above, of functions f(x), g(x) and the composite function, the domain is:

[–3, 6) ∪ (6, ∞)

More can be learned about composite functions at brainly.com/question/13502804

#SPJ1

7 0
1 year ago
2(-5y + 6) + 2(5 - 3.4s)
Andre45 [30]
I'm going to have to go with →-6.8s - 10y + 22 
5 0
3 years ago
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