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WINSTONCH [101]
2 years ago
8

I need help with this problem

Mathematics
1 answer:
gregori [183]2 years ago
4 0

Answer:

[g+2/3g-1] ÷ [g^2+2g/6g+2]

g+2/3g-1 × 6g+2/g^2+2g

g+2/3g-1 × 2(3g +1)/g(g+2)

1/ 3g-1 × 2(3g+1)/g

2(3g +1)÷ g(3g-1)

6g+2 ÷[3g^2-g]

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