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d1i1m1o1n [39]
3 years ago
15

You play basketball at your school's

Mathematics
1 answer:
vaieri [72.5K]3 years ago
8 0

Answer:

20 + 2x = 4x

Step-by-step explanation:

So you are setting the two expressions equal to each other.

buying a membership card  and paying each time looks like this: 20 + 2x where x is the number of times you go to the gym.  20 dollars base then 2 each time you go.

4 each time you go is just 4x

so just set the two equal to each other.

20 + 2x = 4x

If you solve it you will get x = something, which would be the number of times to make the two equal.  

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Out of 24 cookies, <br> 3<br> 4<br> are chocolate chip. How many cookies are chocolate chip?
Yanka [14]

Answer:

18 cookies

Step-by-step explanation:

3/4 = 75%

75% = 0.75

Multiply this by 24 = 18 cookies

7 0
3 years ago
PLS help
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Answer:

There is an error in line 2; segment BE should be a perpendicular bisector.

Step-by-step explanation:

I took the test, i got it right. :)

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2 years ago
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Factor 360t 10t^3 - 120t ^2.
den301095 [7]
Hello:
<span>360t +10t^3 - 120t² = 10t(36t +t² -12t)</span>
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3 years ago
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Helppppppppppppppopo
Vesna [10]
The answer is A, all that was needed was to do the math.

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3 years ago
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F(x) = <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B7%7D%20-%5Csqrt%7Bx%5E2%2B2x-15%7D" id="TexFormula1" title="\sqrt{x+7} -\
elena-s [515]

Answer:

x >= -7  ................(1a)

x >= 3   ...............(2a1)

Step-by-step explanation:

f(x) =  \sqrt{x+7}-\sqrt{x^2+2x-15}  .............(0)

find the domain.

To find the (real) domain, we need to ensure that each term remains a real number.

which means the following conditions must be met

x+7 >= 0  .....................(1)

AND

x^2+2x-15 >= 0 ..........(2)

To satisfy (1),  x >= -7  .....................(1a) by transposition of (1)

To satisfy (2), we need first to find the roots of (2)

factor (2)

(x+5)(x-3) >= 0

This implis

(x+5) >= 0 AND (x-3) >= 0.....................(2a)

OR

(x+5) <= 0 AND (x-3) <= 0 ...................(2b)

(2a) is satisfied with x >= 3   ...............(2a1)

(2b) is satisfied with x <= -5 ................(2b1)

Combine the conditions (1a), (2a1), and (2b1),

x >= -7  ................(1a)

AND

(

x >= 3   ...............(2a1)

OR

x <= -5 ................(2b1)

)

which expands to

(1a) and (2a1)   OR  (1a) and (2b1)

( x >= -7 and x >= 3 )  OR ( x >= -7 and x <= -5 )

Simplifying, we have

x >= 3  OR ( -7 <= x <= -5 )

Referring to attached figure, the domain is indicated in dark (purple), the red-brown and white regions satisfiy only one of the two conditions.

3 0
3 years ago
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