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3 years ago

You play basketball at your school's

Mathematics

1 answer:

vaieri [72.5K]3 years ago

8 0

Answer:

20 + 2x = 4x

Step-by-step explanation:

So you are setting the two expressions equal to each other.

buying a membership card and paying each time looks like this: 20 + 2x where x is the number of times you go to the gym. 20 dollars base then 2 each time you go.

4 each time you go is just 4x

so just set the two equal to each other.

20 + 2x = 4x

If you solve it you will get x = something, which would be the number of times to make the two equal.

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A veterinarian estimated the weight of a puppy to be 7 kg. The actual weight of the puppy was 6.6 kg.

KIM [24]

9514 1404 393

Answer:

absolute error: 0.4 kg
relative error: 6.1%

Step-by-step explanation:

The absolute error is the difference between the estimate and the actual weight:

7.0 kg -6.6 kg = 0.4 kg . . . . absolute error

The relative error is the ratio of the absolute error to the actual weight:

(0.4 kg)/(6.6 kg) × 100% = 6.060606...% ≈ 6.1% . . . . relative error

6 0

3 years ago

This is my last question i swear pls help

Vedmedyk [2.9K]

Answer:

To find a

sin 30=a/6in

1/2=a/6in

2a=6in

a=6in/2

a=3in

To find b

cos 30=b/6in

/3/2=b/6in

2b=/3*6in

b=2/3(two radical three)

I don't get the radical sign so I use / sign on the last 3 steps on the second

8 0

2 years ago

Read 2 more answers

The equation of a circle is (x - 3)2 + (y + 2)2 = 25. The point (8, -2) is on the circle.

Svetlanka [38]

Hello,

Answer A

y=8
=======================

4 0

4 years ago

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An art project has an area of 63.6 square inches. What is the width, in inches, of the project?

miss Akunina [59]

Answer:

Option C . 5.3 in

Step-by-step explanation:

<u><em>The complete question is</em></u>

An art project has an area of 63.6 square inches. What is the width, in inches, of the project?

A rectangle is shown divided into 4 smaller rectangles that are related to the size of the edges. The top edge is labeled 10 inches and 2 inches, above the top two rectangles. The top two rectangles are much larger than the bottom two rectangles

Let

x ----> the length of the art project in inches

y ----> the width of the art project in inches

we know that

The area of the rectangular art project is equal to

$A=xy$