Answer:
Step-by-step explanation:
The table can be computed as:
Advertising Expenses ($ million) Number of companies
25 up to 35 4
35 up to 45 19
45 up to 55 27
55 up to 65 16
65 up to 75 9
TOTAL 75
Let's find the probabilities first:
For 35 up to 45
For 45 up to 55
For 55 up to 65
For 65 up to 75
Chi-Square Table can be computed as follows:
Expense No of Probabilities(P) Expe 
compa cted E (n*p)
nies (O)
25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758
35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362
45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021
55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151
65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650
Using the Chi-square formula:
Null hypothesis:
Alternative hypothesis:
Assume that:
degree of freedom:
= n-1
= 5 -1
= 4
Critical value from 
Decision rule: To reject 
test statistics is greater than 
tabulated.
Conclusion: Since 
is less than critical value 11.667. Then we fail to reject 
Answer:
22
Step-by-step explanation:
Pretend the 10 values in the first sentence are a,b,c,d,e,f,g,h,i,j
Pretend the addition 5 values is k,l,m,n,o
So the mean of all the 15 data is (a+b+c+d+e+f+g+h+i+j+k+l+m+n+o)/15=20
So the sum of all 15 data is a+b+c+d+e+f+g+h+i+j+k+l+m+n+o=300 since 15(20)=300
Now let's look at the first 10: We have their mean so we can write:
(a+b+c+d+e+f+g+h+i+j)/10=19
so a+b+c+d+e+f+g+h+i+j=190 since 10(19)=190
So that means using our first sum equation and our equation sum equation we have
190+k+l+m+n+o=300
k+l+m+n+o=300-190
k+l+m+n+o= 110
So the average of those 5 numbers mentioned in your problem is 110/5=22
AB = CD = √8 ≈ 2.8 units
BC = AD = √2 ≈ 1.4 units
Area of the rectangle ABCD = 3.92 units²
Perimeter of the rectangle ABCD = 8.4 units
<h3>How to Find the Area and Perimeter of a Rectangle?</h3>
Given the coordinates of vertices of rectangle ABCD as:
- A(0,2)
- B(2,4)
- C(3,3)
- D(1,1)
To find the area and perimeter, use the distance formula to find the distance between A and B, and B and C.
Using the distance formula, we have the following:
AB = √[(2−0)² + (4−2)²]
AB = √[(2)² + (2)²]
AB = √8 ≈ 2.8 units
CD = √8 ≈ 2.8 units
BC = √[(2−3)² + (4−3)²]
BC = √[(−1)² + (1)²]
BC = √2 ≈ 1.4 units
AD = √2 ≈ 1.4 units
Area of the rectangle ABCD = (AB)(BC) = (2.8)(1.4) = 3.92 units²
Perimeter of the rectangle ABCD = 2(AB + BC) = 2(2.8 + 1.4) = 8.4 units
Learn more about the area and perimeter of rectangle on:
brainly.com/question/24571594
#SPJ1
Answer: (D) No. The corresponding pairs of sides must also be marked congruent to determine that the triangles are congruent.
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Explanation:
The arc markings tell us how the angles pair up, and which pairs are congruent. Eg: The double-arc angles are the same measure.
Despite knowing that all three pairs of angles are congruent, we don't have enough information to conclude the triangles are congruent overall. We can say they are similar triangles (due to the AA similarity theorem), but we can't say they are congruent or not. We would need to know if at least one pair of sides were congruent, so that we could prove the triangles congruent.
The list of congruent theorems is
- SSS
- ASA
- AAS (or SAA)
- SAS
- HL
- LL
Much of these involve an "S", to indicate "side" (more specifically "pair of sides). Both HL and LL involve sides as well. They are special theorems dealing with right triangles only.
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So in short, we don't have enough info. We would have to know information about the sides. This is why choice D is the answer.
To find the probability of landing on a triangle, you will want find the combined areas of the triangles and the total area of the square target.
Divide the area of the combined areas and the total area to find the probability of landing on a triangle.
A = 1/2bh
1/2 x 8 x 8
A = 32 square inches
32 x 4
128 square inches (areas of triangles)
A = bh
26 x 26
A = 676 square inches
128/676 = 0.189
There is an approximate probability of 0.19 of hitting a triangle.
