Answer:
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Step-by-step explanation:
Answer:
2587mm^3 approx!
Step-by-step explanation:
first you divide the nut into 6 part(in triangle now, by joining centre to each edge)
let's take one part of the triangular shape then area of that part can be found by using 1/2×base×height
i.e, 1/2×13×15=97.5(mm^2)
now when we consider depth of that traingular part,we will get volume of that part as area×depth
i.e, 97.5×6=585(mm^3)
now volume of all the 6 triangular part is 585×6=3510(in mm^3)
now take circular cavity in consideration, it's volume will be π(7^2)6=923(mm^3) approximately
now reqired volume will be volume of that hexagonal part minus that of circular cavity
=3510-923
=2587mm^3
✌️
Answer:
(f+g)(x) = 7x -1 (Answer C)
Step-by-step explanation:
Rewrite these two functions, one above the other, for ease in adding:
f(x) = 5x - 2
+g(x) =2x + 1
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(f+g)(x) = 7x -1
z=(63-84)/3= -21/7= -3
P(x>63)=p(z > -3) = .9987 or 99.87%
