Answer:
j=42.36
Step-by-step explanation:
=15 to original answer
Answer:
Hello your question is incomplete attached below is the correct question
and the solution
answer: A
Step-by-step explanation:
attached below is a detailed solution of the given problem
There exists P and C such that ( ∵ λ1 ≠ λ21 so A is diagonalizable )
Answer:
The number is 91
Step-by-step explanation:
Let x be the ones place digit and y be the tens place digit,
Then the number would be 10y + x,
We have,
y - x = 8
Possible values of y and x = { (8, 0), (9, 1) }
∵ 0 is not the digit of the number,
Hence, y = 9 and x = 1
Therefore, required number = 10(9) + 1 = 90 + 1 = 91
Answer:
.3
Step-by-step explanation:
Answer:

Step-by-step explanation:
(−2x + 6y)(4x − 6y)
To multiply this we use FOIL method
first we multiply -2x with 4x, it becomes -8x^2
Then multiply -2x with -6y, we get 12xy
multiply 6y with 4x, we get 24xy
multiply +6y with -6y, we get -36y^2
Now we commbine all the answers we got

combien like terms
12xy+24xy= 36xy
