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alisha [4.7K]
3 years ago
15

The length of a side of a cube can be determined

Mathematics
1 answer:
seraphim [82]3 years ago
8 0

Answer:

Side of cube = 4 cm

Step-by-step explanation:

Given:

Volume of cube = 64 cm³

Find:

Side of cube

Computation:

Volume of cube = side³

64 = side³

Side of cube = 4 cm

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HELP PLSSSS I will GIve BRainlyest
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The independent is the weight of all the people already on the elevator and the dependent variable is the weight of the elevator after you get on.

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sergeinik [125]

Answer:

1/3

Step-by-step explanation:

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4 0
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Anybody know the correct answer?
earnstyle [38]

Since \csc^2{x}=\frac{1}{\sin^2{x}} and \cot^2{x}=\frac{\cos^2{x}}{\sin^2{x}}, we can rewrite the right side of the equation as

\frac{1}{\sin^2{x}}-\frac{\cos^2{x}}{\sin^2{x}} =\frac{1-\cos^2{x}}{\sin^2{x}}

Using the identity \sin^2{x}+\cos^2{x}=1, we can subtract \cos^2{x} from either side to obtain the identity \sin^2{x}=1-\cos^2{x}

substituting that into our previous expression, the right side of our equation simply becomes

\frac{\sin^2{x}}{\sin^2{x}}=1

We can now write our whole equation as

3\tan^2{x}-2=1

Adding 2 to both sides:

3\tan^2{x}=3

dividing both sides by 3:

\tan^2{x}=1

\tan{x}=\pm1

When 0 ≤ x ≤ π, tan x can only be equal to 1 when sin x = cos x, which happens at x = π/4, and it can only be equal to -1 when -sin x = cos x, which happens at x = 3π/4

4 0
3 years ago
A university wants to build a new residence hall with dorm rooms. The length is 3x+1 ft and the width is x^2-1 ft. If the univer
Masja [62]

Length of room, l = 3x + 1 ft.

Breadth of room, b = x² -1 ft.

Now, it is given that university wants each room to have 195 ft² of living space.

So,

lb = A\\\\(x^2-1)(3x+1)=195\\\\3x^3+x^2-6x-1=195\\\\3x^3+x^2-6x-196=0

So, above equation has two complex root and one real root i.e x = 4.08 ft .

Therefore, Length of room is 13.24 ft and breadth is 15.65 ft.

Hence, this is the required solution.

7 0
3 years ago
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