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3 years ago

Points J, K and L are collinear with J between L and K. If KJ = 2x-3, LJ= 4x-8, solve for x:

Mathematics

1 answer:

notsponge [240]3 years ago

8 0

Your question is incomplete, here is the complete form.

Points J, K and L are collinear with J between L and K. If KJ = 2x - 3, LK = 9x + 7 and LJ = 4x - 8, solve for x:

Answer:

The value of x is -6 ⇒ B

Step-by-step explanation:

∵ J, K, and L are collinear

→ That means they form a straight segment

∵ J is between K and L

→ That means J divides LK into two segments KJ and LJ

∴ LK = KJ + LJ

∵ LK = 9x + 7

∵ KJ = 2x - 3

∵ LJ = 4x - 8

→ Substitute them in the equation above

∴ 9x + 7 = (2x - 3) + (4x - 8)

→ Add the like terms in the right side

∵ 9x + 7 = (2x + 4x) + (-3 - 8)

∴ 9x + 7 = 6x + -11

∴ 9x + 7 = 6x - 11

→ Subtract 7 from both sides

∵ 9x + 7 - 7 = 6x - 11 - 7

∴ 9x = 6x - 18

→ Subtract 6x from both sides

∵ 9x - 6x = 6x - 6x - 18

∴ 3x = -18

→ Divide both sides by 3

∵ $\frac{3x}{3}=\frac{-18}{3}$

∴ x = -6

∴ The value of x is -6

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