Points J, K and L are collinear with J between L and K. If KJ = 2x-3, LJ= 4x-8, solve for x:
1 answer:
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Points J, K and L are collinear with J between L and K. If KJ = 2x - 3, LK = 9x + 7 and LJ = 4x - 8, solve for x:
Answer:
The value of x is -6 ⇒ B
Step-by-step explanation:
∵ J, K, and L are collinear
→ That means they form a straight segment
∵ J is between K and L
→ That means J divides LK into two segments KJ and LJ
∴ LK = KJ + LJ
∵ LK = 9x + 7
∵ KJ = 2x - 3
∵ LJ = 4x - 8
→ Substitute them in the equation above
∴ 9x + 7 = (2x - 3) + (4x - 8)
→ Add the like terms in the right side
∵ 9x + 7 = (2x + 4x) + (-3 - 8)
∴ 9x + 7 = 6x + -11
∴ 9x + 7 = 6x - 11
→ Subtract 7 from both sides
∵ 9x + 7 - 7 = 6x - 11 - 7
∴ 9x = 6x - 18
→ Subtract 6x from both sides
∵ 9x - 6x = 6x - 6x - 18
∴ 3x = -18
→ Divide both sides by 3
∵
∴ x = -6
∴ The value of x is -6
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Answer:
Part a) We should try to eliminate the y's because the coefficients are the same
Part b) The solution is the point (6,-9)
Step-by-step explanation:
Part a) Which variable pair should we try to eliminate?
we have
----> equation 1
----> equation 2
Solve by elimination
We should try to eliminate the y's because the coefficients are the same
Part b) What is the solution to the system?
Multiply equation 2 by -1 both sides
-----> equation 3
Adds equation 1 and equation 3
Find the value of y
The solution is the point (6,-9)