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V125BC [204]
3 years ago
10

I need to find the slopes from two points!show work.i don’t know how to do this

Mathematics
2 answers:
vlada-n [284]3 years ago
7 0

Answer:

slope = 4

Step-by-step explanation:

salantis [7]3 years ago
4 0

Answer:

4

Step-by-step explanation:

Ok.....Since I can't graph it, we can make a table

x       y

3       9

1        1

From 9 to 1, you subtract 8 (this is for the y section)

From 3 to 1, you subtract 2 (this is for the x section)

Now all you have to do is divide the y with the x

y/x = 8/2 = 4

And 4 will be your slope for these two points.

Hope this helped!

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6 0
3 years ago
Can we consider 5√×as monomial? ​
PilotLPTM [1.2K]

Answer:

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5 0
3 years ago
Read 2 more answers
Find the value of sin(a/2) if cosa= 12/13<br>​
daser333 [38]

Answer: sin\frac{a}{2} = ± \frac{1}{\sqrt{26} }

Step-by-step explanation:

We very well know that,

cos2A=1−2sin²A

⟹ sinA = ±\sqrt{(1-} \frac{cos2A}{2} )

As required,  set A = \frac{a}{2}   &   cos a=  \frac{12}{13}    ,thus we get

sin \frac{a}{2} =± \sqrt{\frac{1-cos a}{2} }  

∴ sin\frac{a}{2} =±\sqrt{\frac{1-\frac{12}{13} }{2} } = ± \frac{1}{\sqrt{26} }

   since ,360° < \frac{a}{2} <450°

             ,180° < \frac{a}{2} <225°

Now, we are to select the value with the correct sign. It's is obvious from the above constraints that the angle a/2 lies in the III-quadrant where 'sine' has negative value, thus the required value is negative.

hope it helped!

   

5 0
3 years ago
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Oduvanchick [21]

White figure Area = 128\pi

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Surface Area found with = 2πrh+2πr2

You need to memorize them for tests

Hope that helped!!! k

4 0
4 years ago
Read 2 more answers
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