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Mrac [35]
3 years ago
9

Solve the exponential equation: 3- x = 1

Mathematics
1 answer:
victus00 [196]3 years ago
3 0

~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 3^{2-x}=1\implies 3^2\cdot 3^{-x}=1\implies 3^2\cdot \cfrac{1}{3^x}=1\implies \cfrac{3^2}{3^x}=1 \\\\\\ 3^2=3^x\implies 2=x

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Which polynomial expression represents a sum of cubes? (6 – s)(s2 + 6s + 36) (6 + s)(s2 – 6s – 36) (6 + s)(s2 – 6s + 36) (6 + s)
Nadusha1986 [10]

Answer:

Option 3 is correct that is (6+s)(s^2-6s+36)

Step-by-step explanation:

 We have general formula for sum of cube which is

a^3+b^3=(a+b)(a^2+b^2-ab)

Here, we have a=s and b=6

on substituting the values in the formula we will get

6^3+s^3=(6+s)(s^2+6^2-6s)

After simplification we will get

6^3+s^3=(6+s)(s^2+36-6s)

After rearranging the terms we will get

6^3+s^3=(6+s)(s^2-6s+36) which exactly matches option 3 in the given options.

Therefore, option 3 is correct that is (6+s)(s^2-6s+36)



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Step-by-step explanation:

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