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liraira [26]
3 years ago
6

What is the domain of the inverse of y=4x-3

Mathematics
1 answer:
matrenka [14]3 years ago
7 0
The domain is (-∞, ∞)
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Simplify:<br> 64 ÷ 8 + 6 (2)<br><br> A. 23<br> B. 20<br> C. 17
Iteru [2.4K]

Answer:

B. 20

Step-by-step explanation:

64 ÷ 8 + 6(2)

64 ÷ 8 + 12

8 + 12

20

6 0
2 years ago
Read 2 more answers
Which value is the solution of the equation 5y-4x=-3
Lelechka [254]
I hope this helps you

7 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!!!!!!!!1111 I REALLY NEED HELP I A, BEGGIN YOU GUYS!!!!!!!!!!!!!!!!!!!!!!!!!!! ILL GIVE BRAINLIEST AND
Thepotemich [5.8K]

Answer:

Step-by-step explanation:

4y - 2(5 - y + 4) = 4y - 2(9 - y)

                         = 4y + 9*(-2) - y *(-2)

                         = 4y  - 18 + 2y      {Combine like terms 4y and 2y}

                         = 6y - 18

6y - 18 = 6*y - 6*3

           = 6(y - 3)

6y- 18 =  2 *3y - 2*9

          = 2(3y -9)

2(3y - 9) and 6(y- 3 ) are equivalent to 4y - 2(5- y +4)

Others are not equivalent

3 0
3 years ago
triangle abc has vertices at a(-2 3),B(0,3),c(-1,-1). Find the coordinates of the image after a reflection over the x-axis.
Crazy boy [7]

The new coordinates of the triangle after reflection from x-axis would be  A(-2, -3) , B(0, -3) and C( -1, 1 )

<u>Explanation:</u>

The vertices of the triangle are A(-2 3), B(0,3), C(-1,-1)

The reflection is over the x-axis.

When the reflection is along the x-axis, the coordinates of x does not change. However, the coordinates of y does change.

The negative value of y becomes positive and the positive value of y becomes negative.

Similarly,

A(-2, 3) would become A(-2, -3)

B(0, 3) would become B(0, -3)

C(-1, -1) would become C( -1, 1 )

Therefore, the new coordinates of the triangle after reflection from x-axis would be  A(-2, -3) , B(0, -3) and C( -1, 1 )

6 0
3 years ago
7. A bag of M&amp;Ms contains the following distribution of colors:
lys-0071 [83]

Answer:

a) 21/1240 = 0.017

b) 9/1240 = 7.26*10^-3

c) 3/2480 = 1.21*10^-3

Step-by-step explanation:

There are total 32 M&Ms in the bag

a) Probability that all three are blue M&Ms (without replacement)

         (9/32)*(8*31)*(7/30) = 21/1240 = 0.017

b)     Probability that the first one selected is blue, the second one selected is orange, and the third one selected is red

         (9/32)*(6/31)*(4/30) = 9/1240 = 7.26*10^-3

c)     Probability that the first two selected are red, and the third one selected is yellow

        (4/32)*(3/31)*(3/30) = 3/2480 = 1.21*10^-3

3 0
3 years ago
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