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algol13
3 years ago
6

Whats is the answer to the equation 10+43

Mathematics
2 answers:
Lapatulllka [165]3 years ago
7 0
53.

easy way to do this is line up and add.
liraira [26]3 years ago
5 0

Answer:

53

Step-by-step explanation:

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I need help on this if anyone don’t mind
Minchanka [31]

9514 1404 393

Answer:

  • 4
  • 16

Step-by-step explanation:

For this to have infinitely many solutions, the left side and right side must simplify to the same expression. The left side is already simplified, so we need to find the right numbers for the right side.

Coefficient of x:

  7x = __x + 3x

  4x = __x . . . . . . subtract 3x; next divide by x

  4 = __ . . . . . the required x-coefficient is 4

Constant term:

  -8 = 8 -__

  -16 = -__ . . . . . subtract 8

  16 = __ . . . . . . multiply by -1

__

The numbers that go in the boxes are 4 and 16.

7 0
3 years ago
How is 225 divisible by nine
Ivanshal [37]
A number is divisible by 9 if and only if the sum of its number is a multiple of nine.

2+2+5=9 hence 255 is divisible by 9.
5 0
3 years ago
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GarryVolchara [31]
30.56 hope i helped my gurl
5 0
3 years ago
A quarterback throws an incomplete pass. The height of the football at time t is modeled by the equation h(t) = –16t2 + 40t + 7.
Nostrana [21]
Indicated here when h(t) = 0, we are to find for the time where the football has reached a certain height. 


Then, the values of t would be -0.2 and 2.7.

Since we are to look for the time, it is impossible for us to have an answer that has a negative value. So based from our answer, the solution that we will eliminate is the -0.2 one. Since its value is negative.

So, the correct value would be the 2.7 sec. one.
5 0
3 years ago
Read 2 more answers
Let a and b be real numbers satisfying a^3 - 3ab^2 = 47 and b^3 - 3a^2 b = 52. Find a^2 + b^2.
boyakko [2]

Answer: a²+b² = -99/2

Step-by-step explanation:

Since we are given two equations, this equations will be solved simultaneously to get a² and b²

a³ - 3ab² = 47 ... 1

b³ - 3a² b = 52... 2

From 1, a(a² - 3b²) = 47...3

From 2, b(b² - 3a²) = 52... 4

Adding 3 and 4, we have;

a²+b²-3b²-3a² = 99 (note that a and b will no longer be part of the equations as they have been factored out)

a²+b²-(3b²+3a²) = 99

(a²+b²) -3(b²+a²)= 99

Taking the difference we have

- 2(a²+b²) = 99

a²+b² = -99/2

8 0
3 years ago
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