Answer:
Step-by-step explanation:
25 - 3 is 22. 22 divided by 4.50 is a decimal. But it rounds down to 4. So the most amount of games Tristan can play is 4.
Hope it helps!
Answer:
1. 2(k + 3)
2. 3. 75 + k
Step-by-step explanation:
1. 2x + 6
Since, 2 is a common factor of 2 and 6, we can take that common outside.
So, 2x + 6 = 2(x + 3)
Note that in the initial expression, this 2 was distributed to arrive at 2x + 6.
2. (1.5 + k) + 2.25
This is simple addition. We can simply remove the brackets to have:
1.5 + k + 2.25
Since, the like terms can be added, we will have:
1.5 + 2. 25 + k
= 3. 75 + k
Answer:
2 parts white paint
Step-by-step explanation:
Blue : white
3 : 1
We use 6 parts blue
3 *2 =6
So multiply each part by 2
Blue : white
3*2 : 1*2
6 : 2
She uses 2 parts white paint
1mm:1m
since its just one to one, thats the ratio
Part A;
There are many system of inequalities that can be created such that only contain points C and F in the overlapping shaded regions.
Any system of inequalities which is satisfied by (2, 2) and (3, 4) but is not stisfied by <span>(-3, -4), (-4, 3), (1, -2) and (5, -4) can serve.
An example of such system of equation is
x > 0
y > 0
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the x-axis and to the right of the y-axis is shaded.
Part 2:
It can be verified that points C and F are solutions to the system of inequalities above by substituting the coordinates of points C and F into the system of equations and see whether they are true.
Substituting C(2, 2) into the system we have:
2 > 0
2 > 0
as can be seen the two inequalities above are true, hence point C is a solution to the set of inequalities.
Part C:
Given that </span><span>Natalie
can only attend a school in her designated zone and that Natalie's zone is
defined by y < −2x + 2.
To identify the schools that
Natalie is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining Natalie's zone.
For point A(-3, -4): -4 < -2(-3) + 2; -4 < 6 + 2; -4 < 8 which is true
For point B(-4, 3): 3 < -2(-4) + 2; 3 < 8 + 2; 3 < 10 which is true
For point C(2, 2): 2 < -2(2) + 2; 2 < -4 + 2; 2 < -2 which is false
For point D(1, -2): -2 < -2(1) + 2; -2 < -2 + 2; -2 < 0 which is true
For point E(5, -4): -4 < -2(5) + 2; -4 < -10 + 2; -4 < -8 which is false
For point F(3, 4): 4 < -2(3) + 2; 4 < -6 + 2; 4 < -4 which is false
Therefore, the schools that Natalie is allowed to attend are the schools at point A, B and D.
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