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Marianna [84]
3 years ago
8

How to solve this problem?

Mathematics
1 answer:
arsen [322]3 years ago
7 0
The exact answer is 336
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What is the sum of the solution to the equation 8x^2+2x-3=0 A. 3/8 B.1/4 C-1/4 D. -3/8
SpyIntel [72]
The Answer Is Gonna Be 1/2 Or -3/4.
6 0
3 years ago
When flying at an altitude of 5 miles, the lines of sight to the horizon looking north and south make about a 173.7 degree angle
oksian1 [2.3K]
5 miles high is one of the sides of a triangle depending on accuracy level
h^2=x^2+y^2
we don't have 2 distances
Tan A=O/a
O=a tan A
We solve for O because the angle is at the top of the line going up and we want the opposite angle that is along the ground
O=5×tan(173.7/2)=90.854033512
The distance he can see is:
90.85*2~181.7 miles

Now we need to find the distance between lines:
The north south distance between each line is 69 miles
thus the number of degrees he will see will be:
181.7/69
=2 19/30
7 0
3 years ago
For the equation : y = 2x + 10. Write any two possible solutions in ordered form. (Hint: e.G ( 4, 18))
nalin [4]

Answer:

(0, 10)

and

(1, 12)

5 0
3 years ago
Read 2 more answers
Answer for immediate brainliest
Goryan [66]

Answer:

some

Step-by-step explanation:

4 0
3 years ago
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Can anyone help me understand how to evaluate the limit of this complex fraction?
SSSSS [86.1K]

Answer:

-1/9

Step-by-step explanation:

\lim_{x \to 3} \frac{1/x-1/3}{x-3}

For simplicity, let's multiply top and bottom by 3x:

\lim_{x \to 3} \frac{3-x}{3x(x-3)}

Factor out a -1:

\lim_{x \to 3} \frac{-(x-3)}{3x(x-3)}

Divide top and bottom by x−3:

\lim_{x \to 3} \frac{-1}{3x}

Evaluate the limit:

\frac{-1}{3(3)}\\-\frac{1}{9}

It's important to note that the function doesn't exist at x = 3.  As x <em>approaches</em> 3, the function <em>approaches</em> -1/9.

5 0
3 years ago
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