Answer:
r = 3
Step-by-step explanation:
x^2 + 6x + y^2 - 8y = - 16
Take half the linear term and square it.
x^2 + 6x + (3)^2 + y^2 - 8y + (-4)^2 = - 16
Add the squared amounts to the right.
x^2 + 6x + 9 + y^2 - 8y + 16 = - 16 + 9 + 16
Combine on the right.
x^2 + 6x + 9 + y^2 - 8y + 16 = 9
Represent the 2 quadratics as perfect squares.
(x + 3)^2 + y - 4)^2 = 9
The radius is the square root of 9 which is 3
<u>Answer:</u>
The range of the function y = 2cos x is -2 <y < 2 .
<u>Step-by-step explanation:</u>
We know that cos (0) = 1 and cos (π) = - 1 are the two extreme values which cos x assume when x ∈ R and it is also that cos (x) is a continuous periodic function with period 2π when x ∈ R ,
since ,
cos (x + 2π) = cos x
So, the range of the function y = 2cos x is -2 <y < 2 .
Answer:
B.
Step-by-step explanation:
The table was <em><u>22.5 inches wide</u></em>.
hope this helps!
