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son4ous [18]
3 years ago
14

Please helpppppppp meeeeee

Mathematics
2 answers:
Vaselesa [24]3 years ago
6 0
In order from first pic to last:
10
2
30
70
8
99
1
11
Add 2, divide by 3
-3
podryga [215]3 years ago
6 0

Answer:

Step-by-step explanation:

1: Add 2 divide 3

2: -3

3:1

4:11

5:8

6:99

7:30

8: 70

9:10

10:2

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(time limit!) what is the volume below?<br><br>A) 112 <br>B) 224 <br>C) 784 <br>D) 896
Radda [10]
To find a volume of a cylinder we use the following formula:
v = \pi {r}^{2} h
Plug in the values:

v = \pi \times  {8}^{2}  \times 14
Take the square:
v = \pi \times 64 \times 14
Multiply the numbers:
v =896 \pi {m}^{2}
8 0
3 years ago
SOMEONE PLEASE HELP<br><br><br>and please explain it so I won't get confused further on ​
Pavlova-9 [17]
Number 5 is 110 degrees because it is the same angle as m<2.

Now, to find m<7
A straight line is 180 degrees. One side is already given. m<8+m<7 = 180 degrees. So 180-110=70.

Answers:
4. m<7= 70 degrees

5. m<8= 110 degrees

3 0
3 years ago
Multiply.
aev [14]

Answer:8x3/5=4.8

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
B is the midpoint of ac. Ab = x+9 and bc = 3x-7 find x and ac
natali 33 [55]

To solve this problem, we need to know 2 relationships:

<h2>1. AC = AB + BC</h2>

The distance of AC is the sum of AB and BC.

AC = AB + BC

We know this since the distance of going from A to C (AC) is the same as going from A to B (AB), then B to C (BC).

<h2>2. AB = BC</h2>

The distance of AB is the same as AC.

AB = BC

We know this since B is in the middle of AC, so the distance from B to A (BA) is the same as the distance from B to C (BC).

You can see the attached image (at the bottom) for a visualization of this.

<h2>Putting them together</h2>

Since we know the values of AB and BC...

AB = x+9\\BC = 3x-7

...we can put these values into our 2nd equation and solve for x:

AB = BC\\x + 9 = 3x -7

Add 7 to both sides:

x + 16 = 3x

Subtract x from both sides:

16 = 2x

Divide both sides by 2:

8 = x\\x = 8

Knowing x, we can find the distance of AC using our first equation.

AC = AB + BC

Let's put in the values of AB and BC:

AC = (x+9) + (3x-7)

Before we put in x = 8, we can simplify this:

AC = (x+9) + (3x-7)\\AC = x + 9 + 3x -7\\AC = x + 3x + 9 -7\\AC = 4x + 9 - 7\\AC = 4x+2

We group x and 3x and add those together. Then we subtract 7 from 9.

With this equation, we can put in x = 8:

AC = 4x +2\\AC = 4*8 + 2

Since 4 * 8 = 32:

AC = 4 * 8 + 2\\AC = 32 + 2\\AC = 34

Finally, we have found both x and AC.

<h2>Answer</h2>

x = 8

AC = 34

7 0
4 years ago
Use the diagram on the right. How many planes contain both the line and the point
Aloiza [94]

Part (a)

<h3>Answer: 0</h3>

-------------------

Explanation:

Point P is part of 3 planes or faces of this triangular prism:

  • plane PEF (the front slanted plane)
  • plane PEH (the left triangular face)
  • plane PHG (the back rectangular wall)

Notice how each three letter sequence involves "P", though this isn't technically always necessary. I did so to emphasize how point P is involved with these planes.

Each of the three planes mentioned do not involve line FG

  • Plane PEF only deals with point F
  • Plane PEH doesn't have any of F or G involved
  • plane PHG only involves G

So there are no planes that contain line FG and point P.

==================================================

Part (b)

<h3>Answer: 0</h3>

-------------------

Explanation:

It's the same idea as part (a) earlier. The planes involving point G are

  • plane GQF  (triangular face on the right)
  • plane GFE (bottom rectangular floor)
  • plane GHP (back rectangular wall)

None of these planes have line EP going through them.

As an alternative, we could reverse things and focus on all of the planes connected to line EP. Those 2 planes are

  • plane PEH (triangular face on the left)
  • plane PEF (front slanted rectangular face)

None of these planes have point G located in them.

8 0
3 years ago
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