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Juli2301 [7.4K]
3 years ago
11

4xi + 5yi^8+ 6xi^3 + 2yi^4

Mathematics
1 answer:
Ad libitum [116K]3 years ago
5 0

Answer:

The correct answer is,

7y - 2ix

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3 years ago
What is the value of i 97 – i?<br> –i<br> 0<br> –2i<br> i Superscript 96
Valentin [98]

<em>The question is not clearly readable, but I'm assuming the expression which makes more sense, so you can have a clue</em>

Answer:

i^{97}-i=0

Step-by-step explanation:

<u>Powers of The Imaginary Unit</u>

The imaginary unit i is defined as

i=\sqrt{-1}

The first powers of i are

i^0=1

i^1=i

i^2=(\sqrt{-1})^2=-1

i^3=i.i^2=-i

i^4=i^2.i^2=1

And so on the cycle repeats every four numbers. To find the value of i^{96} we can find the remainder of 96/4=0. So i^{96}=i^0=1

The given expression is

i^{97}-i

Factoring

i(i^{96}-1)

Since i^{96}=1

=i(1-1)=0

The required value is 0

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