Answer:
Given f(x) = 2x + 3 and g(x) = –x2 + 5, find (g o f )(x).
(g o f )(x) = g( f(x))
= g(2x + 3)
= –( )2 + 5 ... setting up to insert the input
= –(2x + 3)2 + 5
= –(4x2 + 12x + 9) + 5
= –4x2 – 12x – 9 + 5
= –4x2 – 12x – 4
Step-by-step explanation:
8x² - 2x - 1 = 0
8x² - 4x + 2x - 1 = 0
4x (2x - 1) + 1 (2x - 1) = 0
(4x + 1)(2x - 1) = 0
4x + 1 = 0 or 2x - 1 = 0
x = -1/4 0r x = 1/2
Answer:
D -- 210
Step-by-step explanation:
In degrees, 7π / 6 is 210°
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Answer:
The change in the car's distance is 8 feet
Step-by-step explanation:
* Lets explain how to solve the problem
- A car is driving away from a crosswalk
- The distance d (in feet) of the car from the crosswalk t seconds
since the car started moving is given by the formula d = t² + 3.5
- The time increasing from 1 second to 3 seconds
- We need to now the change of the car's distance from the crosswalk
∵ The equation of the distance is d = t² + 3.5
∵ The time is 1 second
∴ d = (1)² + 3.5
∴ d = 1 + 3.5 = 4.5 feet
∵ The time is 3 seconds
∴ d = (3)² + 3.5
∴ d = 9 + 3.5 = 12.5 feet
∵ The change of the distance = d of 3 sec - d of 1 sec
∵ d of 3 sec = 12.5 feet
∵ d of 1 sec = 4.5 feet
∴ The change of the distance = 12.5 - 4.5 = 8 feet
∴ The change in the car's distance is 8 feet
