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3 years ago

HELPPPPP PLEASEEEEEE

Mathematics

1 answer:

Verdich [7]3 years ago

8 0

A = 2(9*11) + 1/2(8*11) + 1/2(8 * 9)
A = 198 + 44 + 36
A = 278

Answer
B. 278 in^2

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You get brainliest and points if you help me answer these two questions

Amiraneli [1.4K]

I can’t quite see the question. Mind taking a picture of it closer?

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3 years ago

Given the hyperbola y = 1/x, find the area under the curve between x = 5 and x = 33 to 3 sig. dig. namely: integral subscript 5

Shtirlitz [24]

Answer:

(b) ln(33/5)

Step-by-step explanation:

$\int\limits_{5}^{33} \frac{1}{x} \, dx = \ln(x) \Big|\limits_{5}^{33} = \ln(33) - \ln(5) \\\\= ln(33/5)$

Remember that in general

$\ln(a) - \ln(b) = \ln(a/b)$

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3 years ago

The force of gravity on Mars is different than on Earth. The function of the same situation on Mars would be represented by the

sweet-ann [11.9K]

Answer:

If thrown up with the same speed, the ball will go highest in Mars, and also it would take the ball longest to reach the maximum and as well to return to the ground.

Step-by-step explanation:

Keep in mind that the gravity on Mars; surface is less (about just 38%) of the acceleration of gravity on Earth's surface. Then when we use the kinematic formulas:

$v=v_0+a\,*\,t\\y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2$

the acceleration (which by the way is a negative number since acts opposite the initial velocity and displacement when we throw an object up on either planet.

Therefore, throwing the ball straight up makes the time for when the object stops going up and starts coming down (at the maximum height the object gets) the following:

$v=v_0+a\,*\,t\\0=v_0-g\,*\,t\\t=\frac{v_0}{t}$

When we use this to replace the 't" in the displacement formula, we et:

$y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2\\y-y_0=v_0\,(\frac{v_0}{g} )-\frac{g}{2} \,(\frac{v_0}{g} )^2\\y-y_0=\frac{1}{2} \frac{v_0^2}{g}$

This tells us that the smaller the value of "g", the highest the ball will go (g is in the denominator so a small value makes the quotient larger)

And we can also answer the question about time, since given the same initial velocity $v_0$ , the smaller the value of "g", the larger the value for the time to reach the maximum, and similarly to reach the ground when coming back down, since the acceleration is smaller (will take longer in Mars to cover the same distance)

3 0

3 years ago

I need help: what is this?

givi [52]

Answer:

Step-by-step explanation:

first you have to do the 1+2 to get 3 then you divide 6 by 2 and get 3 then you multiply 3x3 to get 9!

3 0

3 years ago

People attending a football game either supported the home team or the visiting team. if 1369 of the people attending supported

Masja [62]

Given the number of the people attending the football game, the percentage supporters for the home team is 37%.

<h3>What is Percentage?</h3>

Percentage is simply number or ratio expressed as a fraction of 100.

It is expressed as;

Percentage = ( Part / Whole ) × 100%

Given the data in the question;

Number of home team supporters nH = 1369

Number of visting team supporters nV = 2331

Percentage of supporters for home team PH = ?

For we determine the total number of people attending the football game;

nT = nH + nV

nT = 1369 + 2331

nT = 3700

Now, using the perecentage formula above, we find the Percentage of supporters for home team PH

Percentage = ( Part / Whole ) × 100%

PH = ( nH/ nT) × 100%

PH = ( 1369/ 3700) × 100%

PH = 0.37 × 100%

PH = 37%

Therefore, given the number of the people attending the football game, the percentage supporters for the home team is 37%.

Learn more about Percentages here: brainly.com/question/24159063

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2 years ago