Answer:
B. The evidence is very strong - there is NO difference in the proportion of Republicans between the two areas of town.
Step-by-step explanation: Generally, a p-value of less than 0.05 is described as a strong evidence in favour of the null hypothesis. A p-value also known as the probability value is also known to provide the smallest level of evidence at which the null hypothesis would be rejected.
In the question, The p-value is 0.105 which is bigger in value than 0.05 which means there is no significant difference between the evidence and the null hypothesis.
This is known as Einstein's proof, not because he was the first to come up with it, but because he came up with it as a 15 year old boy.
Here the problem is justification step 2. The written equation
BC ÷ DC = BC ÷ AC
is incorrect, and wouldn't get us our statement 2, which is correct.
For similar triangles we have to carefully pair the corresponding parts to get our ratios right:
ABC ~ BDC means AB:BD = BC:DC = AC:BC so BC/DC=AC/BC.
Justification 2 has the final division upside down.
The angle between w and u is approximately
Answer:
y = -2/3 + 18
Step-by-step explanation:
2x + 3y = 18 ----- here is the equation...
-2x - 2x ----- bring the 2x to the other side
3y = -2x + 18 ----- now you have to divide everything by 3 to get y by itself
y = -2/3 + 18 ----- Done!
Ok so this question is a bit complicated, but it's easier to understand if you break it down into smaller parts!
1) First, you know that ABGF is half the perimeter of ACDE. This means that the length of one side of ABGF must be 1/2 the length of one side of ACDE.
>> You can think of this by putting in random numbers. Say the perimeter of the larger square is 24 and the perimeter of the smaller square is 12. That means one side of the larger square of 24/4 (b/c four sides) = 6 and one side of the smaller square is 12/4 = 3!
2. Ok know you know the lengths of the sides relative to each other, but you're only given one value: 4in. Since the smaller square has sides that are 1/2 the larger squares, you know that it makes up 1/4 of the larger square! So imagine 4 of those smaller squares filling up that larger square to make a 2 by 2. It just so happens that 4in is the diagonal going through one of our imaginary squares, which is equal in size to ABGF!
3. Now use the 45-45-90 rule to figure out the length of one side of that imaginary square because the 4in diagonal splits that imaginary square into two of those 45-45-90 triangles. You know the hypotenuse of that triangle is 4in. That means one of the legs is 4/✓2 (since the rule says that the hypotenuse and the leg are in a ✓2:1 ratio). And like we said before the length of that leg is the length of the side of our imaginary square. And our imaginary square must be the same size as ABGF! So now we know the side of the smaller square to be 4/✓2!
4. Multiply the side of the smaller square by 2 to get the side of our larger square. (4/✓2)*2=8/✓2
5. Now to find the area of the shaded region, just find the area of the smaller square ABGF and subtract from the larger square ACDE. Use equation for the area of a square!

where s=the length of one side.
The length of one side of the smaller square is 4/✓2. So it's area is:

The length of one side of the larger square is 8/✓2. So it's area is:

Now subtract. 32-8=24! :)
Hope this helps! Let me know if you have any questions.