Answer:
thx lol
Step-by-step explanation:
The areas are as follows:
Deck 1: 5 * 5 = 25ft squared
Deck 2: 5 * 7 = 35ft squared
Deck 3: 5 * 9 = 45ft squared.
They increase by 10ft squared each time.
Answer:
C(x) = 0.2x^5 - x^2 + 6000
Step-by-step explanation:
Given in the question are restated as follows:
Marginal cos = C'(x) = x^4 - 2x ...................... (1)
Note that marginal cost (C'(x)) refers to the change in the total cost (C(x)) as a result of one more unit increase in the quantity produced. That is, MC refers to the additional cost incurred in order to produce one more unit of a good.
Therefore, TC can be obtained by integrating equation (1) as follows:
C(x) = ∫C'(x) = ∫[x^4 - 2x]dx
C(x) = 1/5x^5 - 2/2x^2 + F ................................ (2)
Where F is the fixed cost. Since the fixed cost is given as $6,000 in the question, we substitute it for F into equation (2) and solve as follows:
C(x) = 0.2x^5 - x^2 + 6000 ......................... (3)
Equation (3) is the total cost function C.
Sum of interior angles of a polygon = (n-2)180 [where n = no. of sides]
(n-2)180 = 720
n-2 = 720/180 = 4
n-2 = 4
n = 4+2 = 6
So it is a 6 sided shape (Hexagon)
is undefined if the argument
is negative, so you first need to require that
We're not done yet, though, because
still doesn't exist when
, so we remove this from the domain and we're left with
, or in interval notation,
To find the range, consider the limits of the function as you approach either endpoint of the domain.
Since
is positive everywhere, the range is