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Vera_Pavlovna [14]
3 years ago
6

If tan x=2021 x=20/21 and π< x < 3π/2 what is cos⁡(x+π/2)?

Mathematics
1 answer:
Flura [38]3 years ago
7 0

Answer:

42Sin

Step-by-step explanation:

Speed it up

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Can someone help me with 16 and 20? If you’re supposed to write a contrapositive and inverse, but the word not is already in the
Dmitry_Shevchenko [17]
Since 2 'not's cancel out, 16's contrapositive is 'If the light will go on, then the fuse has not blown'. In addition, the inverse would be 'If the fuse has not blown, then the light will go on'. I challenge you to do 20 using this information!
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3 years ago
PLEASE HELP ME
lys-0071 [83]
Answer: The answer is the 3rd one
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Which graph represents the solution set of the system of inequalities? {x+y&lt;12 y≥x−4
RSB [31]

Answer: The graph in the bottom right-hand corner

(see figure 4 in the attached images below)

===========================================

Explanation:

Let's start off by graphing x+y < 1. The boundary equation is x+y = 1 since we simply change the inequality sign to an equal sign. Solve for y to get x+y = 1 turning into y = -x+1. This line goes through (0,1) and (1,0). The boundary line is a dashed line due to the fact that there is no "or equal to" in the original inequality sign. So x+y < 1 turns into y < -x+1 and we shade below the dashed line. The "less than" means "shade below" when y is fully isolated like this. See figure 1 in the attached images below.

Let's graph 2y >= x-4. Start off by dividing everything by 2 to get y >= (1/2)x-2. The boundary line is y = (1/2)x-2 which goes through the two points (0,-2) and (4,0). The boundary line is solid. We shade above the boundary line. Check out figure 2 in the attached images below.

After we graph each individual inequality, we then combine the two regions on one graph. See figure 3 below. The red and blue shaded areas in figure 3 overlap to get the purple shaded area you see in figure 4, which is the final answer. Any point in this purple region will satisfy both inequalities at the same time. The solution point cannot be on the dashed line but it can be on the solid line as long as the solid line is bordering the shaded purple region. Figure 4 matches up perfectly with the bottom right corner in your answer choices.

5 0
3 years ago
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On this corrdinate plane UVW has been transformed to form image U’ V’ W’.
egoroff_w [7]

Answer:

C

Step-by-step explanation:

Translate the image 2 units right and 1 unit up. Then rotate the image 180°.

Take the coordinate W, it is at (2, 4).

Translate 2 units right (add 2 to the x coordinate) and 1 up (add 1 to the y coordinate)

(2, 4) ------> (2 + 2, 4 + 1) -------> (4, 5)

A rotation of 180° (doesn't matter the direction) makes the coordinates their opposites. Positives become negatives and negatives become positive.

(4, 5) -------> (-4, -5)

8 0
2 years ago
Graph the functions and identify the domain and range. y=-1.5x^2
erma4kov [3.2K]
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8 0
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