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Marta_Voda [28]
1 year ago
12

if a runner finishes the 26.2. mille race in 4 hours and 37 mins and Wilson kipping finish in 4 minutes and 43 seconds per mile

how much faster was kipsang then the average runner
Mathematics
1 answer:
Neporo4naja [7]1 year ago
4 0

Answer

a) Wilson Kipsang is 7.046 miles per hour faster than the average runner.

Solution is presented below under Explanation.

b) Wilson Kipsang is 2.24 times faster than the average runner.

c) When the average runner is at mile 6, Kipsang will be at mile 13.45.

d) Kipsang's record time = 2 hours, 3 minutes, 34.6 seconds

Explanation

To solve this, we will calculate the speed of the average runner and then the speed of Wilson Kipsang

Speed = (Distance/Time)

For the average runner

Distance = 26.2 miles

Time = 4 hours 37 mins = 4 hours + (37/60) = 4.617 hours

Speed = (Distance/Time)

Speed = (26.2/4.617)

Speed = 5.675 miles per hour

For Wilson Kipsang

Distance = 1 mile

Time = 4 minutes 43 seconds = (4/60) + (43/3600) = 0.0667 + 0.01194 = 0.0786 hour

Speed = (Distance/Time)

Speed = (1/0.0786) = 12.721 miles per hour

So, now, we are asked to find how much faster than the average runner is Wilson Kipsang

Wilson Kipsang's speed = 12.721 miles per hour

Average runner's speed = 5.675 miles per hour

Wilson Kipsang is faster than the average runner by

(12.721 - 5.676) = 7.046 miles per hour

b) We are asked to find how many times faster than the average runner Wilson Kipsang is.

Let the number of times he is faster than the average runner be x

Wilson Kipsang's speed = 12.721 miles per hour

Average runner's speed = 5.675 miles per hour

(5.675) (x) = (12.721)

Divide both sides by 5.675

x = (12.721/5.675)

x = 2.24 times

c) If the average runner is at mile 6, where would Kipsang be?

To do this, we will find the time it takes the average runner to be at mile 6, then use that time to find where Kipsang would be.

Speed = (Distance/Time)

By cross multiplying, we see that

Time = (Distance/Speed)

For the average runner

Distance = 6 miles

Speed = 5.675 miles per hour

Time = (Distance/Speed)

Time = (6/5.675) = 1.057 hours

For Wilson Kipsang,

Speed = (Distance/Time)

By cross multiplying

Distance = (Speed) (Time)

Speed = 12.721 miles per hour

Time = 1.057 hours

Distance = (Speed) (Time)

Distance = (12.721) (1.057)

Distance = 13.45 miles

d) We were told that for Kipsang

1 mile = 4 minutes 43 seconds

26.2 miles = 26.2 (4 minutes 43 seconds)

26.2 miles = 26.2 (283 seconds) = 7414.6 seconds

We can then convert this further

7414.6 seconds = 2 hours, 3 minutes, 34.6 seconds

Hope this Helps!!!

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HELP
Ket [755]

Given the radius of 50 miles and the line joining the cities at (0, 56) and (58, 0), the transmitter signal can be picked during 59.24 miles of the drive.

<h3>How can the duration of signal reception be found?</h3>

Radius of broadcast of the transmitter = 50 miles

Location of starting point = 56 miles north of the transmitter

Location of destination city = 58 miles east of the transmitter

Therefore we have;

Slope of the line joining the two cities

= 56 ÷ (-58) = -0.966

Which gives the equation of the line as follows;

y = -0.966•x + 56

The equation of the circle is;

{x}^{2}  +  {y}^{2}  =  {50}^{2}

{x}^{2}  +  { ( - 0.966x + 56)}^{2}  =  {50}^{2}

1.933156•x^2 - 108.192•x + 636 = 0

Which gives;

  • x = 6.67 or x = 49.29

Therefore;

When x = 6.67, we have;

  • y = -0.966 × 6.67 + 56 = 49.56

When x = 49.29, we have;

  • y = -0.966 × 49.29 + 56 = 8.4

The length of the drive, during which the driver can pick the signal, <em>l</em>, is therefore;

l = √((49.56-8.4)^2 + (49.29-6.67)^2) = <u>59.24 miles</u>

  • The length of the drive during which the signal is received is 59.24 miles

Learn more about the equation of a circle here:

brainly.com/question/502872

#SPJ1

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We want this quantity to be at most 50, so it must be less than or equal to 50:

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