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Vsevolod [243]
2 years ago
11

-6p - 20 = -2p +4(1 - 3p)

Mathematics
2 answers:
kirza4 [7]2 years ago
7 0

Answer:

p = 3

Hope this helps

Ann [662]2 years ago
4 0

Answer:

−

6

−

2

0

=

−

2

+

4

(

1

−

3

)

−

6

−

2

0

=

−

2

+

4

(

−

3

+

1

)

2

Distribute

−

6

−

2

0

=

−

2

+

4

(

−

3

+

1

)

−

6

−

2

0

=

−

2

−

1

2

+

4

3

Combine like terms

−

6

−

2

0

=

−

2

−

1

2

+

4

−

6

−

2

0

=

−

1

4

+

4

4

Add

2

0

20

20

to both sides of the equation

−

6

−

2

0

=

−

1

4

+

4

−

6

−

2

0

+

2

0

=

−

1

4

+

4

+

2

0

5

Simplify

Add the numbers

Add the numbers

−

6

=

−

1

4

+

2

4

6

Add

1

4

14p

14p

to both sides of the equation

−

6

=

−

1

4

+

2

4

−

6

+

1

4

=

−

1

4

+

2

4

+

1

4

7

Simplify

Combine like terms

Combine like terms

8

=

2

4

8

Divide both sides of the equation by the same term

8

=

2

4

8

8

=

2

4

8

9

Simplify

Cancel terms that are in both the numerator and denominator

Divide the numbers

=

3

Solution

=3

Step-by-step explanation:

please give me brainliest

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After traveling exactly half of its journey from station A to station B, a train was held up for 10 minutes. In order to arrive
Alex17521 [72]
Let's define variables:
 s = original speed
 s + 12 = faster speed
 The time for the half of the route is:
 60 / s
 The time for the second half of the route is:
 60 / (s + 12)
 The equation for the time of the trip is:
 60 / s + 60 / (s + 12) + 1/6 = 120 / s
 Where,
 1/6: held up for 10 minutes (in hours).
 Rewriting the equation we have:
 6s (60) + s (s + 12) = 60 * 6 (s + 12)
 360s + s ^ 2 + 12s = 360s + 4320
 s ^ 2 + 12s = 4320
 s ^ 2 + 12s - 4320 = 0
 We factor the equation:
 (s + 72) (s-60) = 0
 We take the positive root so that the problem makes physical sense.
 s = 60 Km / h
 Answer:
 
The original speed of the train before it was held up is:
 
s = 60 Km / h
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