Answer:
If you were look for the cords for the blue one. It will be (-5,4) for O (-2,1) for W and (-7,-3) for N
If it was for the Green one. It will be (-5,-2) for 'O (-1,-2) for 'W and (-5,-7) for 'N
Hope This Helped
Area= i^2 + 4i
Area= length x width
Length (y)= i + 4
Width (i)=i
Answer:
Option C .
Step-by-step explanation:
We would like to solve the below <u>quadratic </u><u>equation</u><u> </u>,

Step 1 : <u>E</u><u>q</u><u>u</u><u>a</u><u>t</u><u>e</u><u> </u><u>f</u><u>(</u><u>x</u><u>)</u><u> </u><u>w</u><u>i</u><u>t</u><u>h</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>


Step 2 : <u>F</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u>i</u><u>s</u><u>e</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>R</u><u>H</u><u>S</u><u> </u><u>:</u><u>-</u>



Step 3 : <u>E</u><u>q</u><u>u</u><u>a</u><u>t</u><u>e</u><u> </u><u>e</u><u>a</u><u>c</u><u>h</u><u> </u><u>f</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u> </u><u>w</u><u>i</u><u>t</u><u>h</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>



<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u> </u><u>o</u><u>p</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>C</u><u> </u><u>i</u><u>s</u><u> </u><u>c</u><u>o</u><u>r</u><u>r</u><u>e</u><u>c</u><u>t</u><u> </u><u>.</u>
Step-by-step explanation:
(x^4)^3=(x^3)^4 , true
=> x^(4×3) = x^(3×4) = x^12
13^4 x 13^7= (13^4)^7, false
13^(4+7) = 13^11
(13^4)^7 = 13^(4×7) = 13^28
y^5 x y^0/y^3=(y^2)^1 , true
y^5 x y^0/y^3 = y^(5+0-3) = y^2
(y^2)^1 = y^(2×1) = y^2
q^0 x q^5/q^2=(q^3)^2/q^3, true
q^0 x q^5/q^2= q^(0+5-2)= q^3
(q^3)^2/q^3 = q^(3×2-3) = q^3
125 = 5^3 = 25 * 5

The simplification you are trying to do involves finding the prime factorization of a number. Since 125 is not divisible by 2, move on to 3. 125 is also not divisible by 3, so move on to 5. Then 125/5 = 25, and 25/5 = 5, so 125 = 5^3. The prime factorization of 125 is 5^3.