1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
liraira [26]
3 years ago
5

Are 3/5 and 18/32 equivalent ratios? Explain how you know (be specific). If you just say yes or no you will not get full credit.

Mathematics
1 answer:
Artist 52 [7]3 years ago
3 0

Answer:

No

Step-by-step explanation:

As, if we try to simplify 18/32, it will be 9/16

So obviously 9/16 is not equal to 3/5

Here 3 x 6 = 18

5 x 6 = 30

So we will get 18/30, not 18/32

You might be interested in
Write the product in its simplest form:<br> c•9c
konstantin123 [22]
I belive it is going to be 9c but i could be wrong
5 0
2 years ago
Read 2 more answers
Emily wants to have her Photo album printed
julsineya [31]
Please provide us with more info, then we'll gladly answer
6 0
3 years ago
In the Midpoint Rule for triple integrals we use a triple Riemann sum to approximate a triple integral over a box B, where f(x,
Tomtit [17]

To approximate the volume with 8 boxes, we have to split up the interval of integration for each variable into 2 subintervals, [0, 1] and [1, 2]. Each box will have midpoint m_{i,j,k} that is one of all the possible 3-tuples with coordinates either 1/2 or 3/2. That is, we're sampling f(x,y,z)=\cos(xyz) at the 8 points,

(1/2, 1/2, 1/2)

(1/2, 1/2, 3/2)

(1/2, 3/2, 1/2)

(3/2, 1/2, 1/2)

(1/2, 3/2, 3/2)

(3/2, 1/2, 3/2)

(3/2, 3/2, 1/2)

(3/2, 3/2, 3/2)

which are captured by the sequence

m_{i,j,k}=\left(\dfrac{2i-1}2,\dfrac{2j-1}2,\dfrac{2k-1}2\right)

with each of i,j,k being either 1 or 2.

Then the integral of f(x,y,z) over B is approximated by the Riemann sum,

\displaystyle\iiint_B\cos(xyz)\,\mathrm dV\approx\sum_{i=1}^2\sum_{j=1}^2\sum_{k=1}^2\cos m_{i,j,k}\left(\frac{2-0}2\right)^2

=\displaystyle\sum_{i=1}^2\sum_{j=1}^2\sum_{k=1}^2\cos\frac{(2i-1)(2j-1)(2k-1)}8

=\cos\dfrac18+3\cos\dfrac38+3\cos\dfrac98+\cos\dfrac{27}8\approx\boxed{4.104}

(compare to the actual value of about 4.159)

4 0
3 years ago
Help me plz help me plz
Lisa [10]

Answer:

A: 1 crackers = 95/4 cals

B: mass= 16/4

c: 15/4

4 0
3 years ago
Read 2 more answers
Find the length of the third side. If necessary, round to the nearest tenth.
Mama L [17]

Answer:

24

Step-by-step explanation:

Use the pythagorean theorem.

7 0
3 years ago
Other questions:
  • Greg washes cars on Saturday at his dad’s car dealership. His dad pays him $25 plus $10 for each car that he washes. Write an eq
    6·1 answer
  • A machine can never be 100% efficient because some work is always lost due to______?
    11·1 answer
  • Gary can ride his bike 6 miles in 20 minutes. At this rate, how many miles can he ride in 100 minutes?
    14·2 answers
  • What is the volume, in cubic centimeters, of this cylinder? Please use 3.14 for π.
    10·1 answer
  • Rolling two sixes in a row on a number cube. Dependent Or Independent?
    10·1 answer
  • The square root of 100
    11·2 answers
  • For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive term
    5·1 answer
  • Please Help!!! I have no clue what the answer is.
    7·1 answer
  • Will's band played 33 shows in three months. How many shows per month did they play?
    15·1 answer
  • Lend a hand yall! Brainliest Help me out
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!