1) The caterpillar was already at 4.5 feet so 4.5 will be added. If it crawls upwards 38 of an inch every minute and the amount of minutes is not specified, this will be represented as 38x. That means the answer is C. f(x) = 38x + 4.5
2) Substitute the known values into the equation. There are 7 people at $8.25 a person, which is a total of $57.75 <u>I used 7 because he invites 6 friends, plus himself. </u>He only has $50 on his gift card, so he won't have enough to cover the cost. The answer is A.
3) They start out with 40lbs and recieve 120 more. They have 160lbs in total. If they sell 8lbs a day for 5 days, thats 8*5 or 40lbs total. 160 - 40 = 120lbs left after 5 days. I'd say the answers are A, B, and D.
4) I think the answer would be C because 1,500 is used to find the number of grams of isotope present after t years. The number of grams can't be 1,500. I hope that makes sense because I'm not sure how to explain it.
5) The growth factor is 2 (2x, x being the number of hours). Multiply by 15 because the lab has 15 of them. The answer is B. f(x) = 15 * 2x
I hope this helps you! I'm sorry if I got any of them wrong!
Answer:
i accidentaly put awnser and i dont know how to get out of here
Step-by-step explanation:
Answer:
500
Step-by-step explanation:
It's a box with a square base, so let's say the width and length are x and the height is y.
The surface area of the box without the top is:
A = x² + 4xy
300 = x² + 4xy
The volume of the box is:
V = x²y
Solve for y in the first equation and substitute into the second:
y = (300 − x²) / 4x
V = x² (300 − x²) / 4x
V = x (300 − x²) / 4
V = 75x − ¼ x³
To optimize V, find dV/dx and set to 0:
dV/dx = 75 − ¾ x²
0 = 75 − ¾ x²
x = 10
So the volume of the box is:
V = 75x − ¼ x³
V = 500
The maximum volume is 500 cm³.
Average rate of the function: 3
Step-by-step explanation:
The function in this problem is
The average rate of change of a function over an interval 
is given by
where
are the values of the function calculated in 
respectively
For the function in this problem we have:
, so
, so
So, the average rate of change is
Learn more about rate of change:
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