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3 years ago

Which is the solution to the inequality? y+15 -12 C.y 18

Mathematics

1 answer:

const2013 [10]3 years ago

7 0

Answer:

wait im confused can u put the numbers together but this is what i got from y+15-12

y+3

Step-by-step explanation:

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The data in the line plot show how many pages each student read last night. Which is the best measure of variability?

AVprozaik [17]

Answer: D range
I hope this helps tou!

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3 years ago

Mr. Hare left at 8:00 a.m. and is traveling 50 miles per hour. Mrs. Hare left at 9:00 a.m. and is traveling at 55 miles per hour

SVETLANKA909090 [29]

Answer: B 8:00pm

Step-by-step explanation:

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3 years ago

The use of mathematical methods to study the spread of contagious diseases goes back at least to some work by Daniel Bernoulli i

harina [27]

Answer:

$y(t) = y_o e^{\beta t}$

$x(t) = x_o e^{\frac{-\alpha y_o }{\beta }[e^{-\beta t} - 1] }$

$\lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }$

Step-by-step explanation:

From the question we are told that

$\frac{dy}{y} = -\beta dt$

Now integrating both sides

$ln y = \beta t + c$

Now taking the exponent of both sides

$y(t) = e^{\beta t + c}$

=> $y(t) = e^{\beta t} e^c$

Let $e^c = C$

$y(t) = C e^{\beta t}$

Now from the question we are told that

$y(0) = y_o$

Hence

$y(0) = y_o = Ce^{\beta * 0}$

=> $y_o = C$

$y(t) = y_o e^{\beta t}$

From the question we are told that

$\frac{dx}{dt} = -\alpha xy$

substituting for y

$\frac{dx}{dt} = - \alpha x(y_o e^{-\beta t })$

=> $\frac{dx}{x} = -\alpha y_oe^{-\beta t} dt$

Now integrating both sides

$lnx = \alpha \frac{y_o}{\beta } e^{-\beta t} + c$

Now taking the exponent of both sides

$x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} + c}$

=> $x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} } e^c$

Let $e^c = A$

=> $x(t) =K e^{\alpha \frac{y_o}{\beta } e^{-\beta t} }$

Now from the question we are told that

$x(0) = x_o$

$x(0)=x_o =K e^{\alpha \frac{y_o}{\beta } e^{-\beta * 0} }$

=> $x_o = K e^{\frac {\alpha y_o }{\beta } }$

divide both side by $(K * x_o)$

=> $K = x_o e^{\frac {\alpha y_o }{\beta } }$

$x(t) =x_o e^{\frac {-\alpha y_o }{\beta } } * e^{\alpha \frac{y_o}{\beta } e^{-\beta t} }$

=> $x(t)= x_o e^{\frac{-\alpha * y_o }{\beta} + \frac{\alpha y_o}{\beta } e^{-\beta t} }$

=> $x(t) = x_o e^{\frac{\alpha y_o }{\beta }[e^{-\beta t} - 1] }$

Generally as t tends to infinity , $e^{- \beta t}$ tends to zero

$\lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }$

5 0

3 years ago

Sprout problem: California farmer of sprouts deals mainly with alfalfa sprouts and brussels sprouts. He has hired you to optimiz

vovangra [49]

Answer:

see attached

Step-by-step explanation:

In the attached, the feasible region is white, and all excluded regions are shaded. When there are so many inequalities, it is easier to see the solution (feasible region) this way. The boundary lines are dashed because they are not excluded. That is, each boundary line is part of the feasible region.

The vertices of the feasible region are shown to aid in any optimization you might want to do. We have shown the values that would apply if there were a constraint y ≥ 0, which is not on your list. (We assume pounds of Brussels sprouts will not be negative.)

If you actually do the shading required by the problem statement, you will be shading on the opposite side of each of the lines shown, and you would draw the lines as solid.

7 0

3 years ago

I WiLL GiVe BrAnYeSt

Phoenix [80]

Answer:

the answer is 529

Step-by-step explanation:

divide 7,406 and 14 and the answer is 529

7 0

3 years ago