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AlladinOne [14]
1 year ago
9

type the correct answer in the Box spell all words correctly which type of coordinates does Andrews. Take Andrew studying mathem

atics and studying about the (blank (coordinate system in this system the coordinates of the of a point are dependent on the distance of the point from the origin and the angle of the start of the points substance at the origin
Mathematics
1 answer:
ahrayia [7]1 year ago
6 0

Where the coordinates of a points pedepend on the distance to the origin of the coordinate system and also depend on the angle, the coordinate system is a POLAR coordinate system.

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Please help i need this done soon!
Kamila [148]

Answer:

this is my old account and these still dont have answers

Step-by-step explanation:

6 0
3 years ago
What are the answers to these thank you and please tell me how to get it
mote1985 [20]
5-3(1/2x+2)=-7
-3(1/2x+2)=-7-5
(1/2x+2)=4
1/2x=2
x=4
just to give u an idea
4 0
3 years ago
Factor: (a+3)^2 -a(a+3)
lutik1710 [3]

Answer:

3(a +3)

Step-by-step explanation:

(a+3)^2 -a(a+3)

FOIL

a^2 +3a+3a+9 -a(a+3)

Distribute

a^2 +3a +3a +9 -a^2 -3a

Combine like terms

3a +9

FACTOR out a+3

(a+3)( a+3 -a)

(a+3) (3)

3(a+3)

6 0
3 years ago
Read 2 more answers
(c). It is well known that the rate of flow can be found by measuring the volume of blood that flows past a point in a given tim
aleksklad [387]

(i) Given that

V(R) = \displaystyle \int_0^R 2\pi K(R^2r-r^3) \, dr

when R = 0.30 cm and v = (0.30 - 3.33r²) cm/s (which additionally tells us to take K = 1), then

V(0.30) = \displaystyle \int_0^{0.30} 2\pi \left(0.30-3.33r^2\right)r \, dr \approx \boxed{0.0425}

and this is a volume so it must be reported with units of cm³.

In Mathematica, you can first define the velocity function with

v[r_] := 0.30 - 3.33r^2

and additionally define the volume function with

V[R_] := Integrate[2 Pi v[r] r, {r, 0, R}]

Then get the desired volume by running V[0.30].

(ii) In full, the volume function is

\displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

Compute the integral:

V(R) = \displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

V(R) = \displaystyle 2\pi K \int_0^R (R^2r-r^3) \, dr

V(R) = \displaystyle 2\pi K \left(\frac12 R^2r^2 - \frac14 r^4\right)\bigg_0^R

V(R) = \displaystyle 2\pi K \left(\frac{R^4}2- \frac{R^4}4\right)

V(R) = \displaystyle \boxed{\frac{\pi KR^4}2}

In M, redefine the velocity function as

v[r_] := k*(R^2 - r^2)

(you can't use capital K because it's reserved for a built-in function)

Then run

Integrate[2 Pi v[r] r, {r, 0, R}]

This may take a little longer to compute than expected because M tries to generate a result to cover all cases (it doesn't automatically know that R is a real number, for instance). You can make it run faster by including the Assumptions option, as with

Integrate[2 Pi v[r] r, {r, 0, R}, Assumptions -> R > 0]

which ensures that R is positive, and moreover a real number.

5 0
3 years ago
Joong Ki paid a total of ₱90 for 6 singkamas and 11 ponkans. If a singkamas and a ponkan cost ₱10, how much does each cost? ANSW
Serggg [28]

Step-by-step explanation:

singkamas: 60 pesos

ponkan: 110 pesos

5 0
3 years ago
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