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Mkey [24]
3 years ago
14

How much will it cost to print a circular sign with a radius of 1.5 feet if the printing company charges $29 per square foot? Us

e A = πr2, where π is approximately 3.14. (Round your answer to the nearest cent.)
Mathematics
1 answer:
RUDIKE [14]3 years ago
7 0

Answer:

$204.89

Step-by-step explanation:

Step 1

We have to first find the area of the circular sign.

Since the sign is circular in shape, we use the Area of Circle.

Area of a Circle = πr²

r = 1.5 feet

π = 3.14

Area of a Circle = 3.14 × 1.5²

= 7.065ft² or 7.065 square feet.

Step 2

We find out how much it cost to print the circular sign.

We are told in the question that

The printing company charges $29 per square foot

Hence,

1 square foot = $29

7.065 square feet =

Cross multiply

= 7.065 × $29

=$ 204.885

Approximately to the nearest cent, $204.89

Therefore, it will cost $204.89 to print the circular sign

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The average THC content of marijuana sold on the street is 9.3%. Suppose the THC content is normally distributed with standard d
velikii [3]

Answer:

a) X \sim N(9.3,1)  

b) P(X>9.2)=P(\frac{X-\mu}{\sigma}>\frac{9.2-\mu}{\sigma})=P(Z>\frac{9.2-9.3}{1})=1-P(Z

c) The value of height that separates the bottom 75% of data from the top 25% is 9.9745.  

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(9.3,1)  

Where \mu=9.3 and \sigma=1

3) Part b

We are interested on this probability

P(X>9.2)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>9.2)=P(\frac{X-\mu}{\sigma}>\frac{9.2-\mu}{\sigma})=P(Z>\frac{9.2-9.3}{1})=1-P(Z

4) Part c

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.25   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.75 of the area on the left and 0.25 of the area on the right it's z=0.6745. On this case P(Z<0.6745)=0.75 and P(z>0.6745)=0.25

If we use condition (b) from previous we have this:

P(X  

P(Z

But we know which value of z satisfy the previous equation so then we can do this:

z=0.6745

And if we solve for a we got

a=9.3 +1*0.6745=9.9745

So the value of height that separates the bottom 75% of data from the top 25% is 9.9745.  

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