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siniylev [52]
3 years ago
9

Put the number by which one you answer and don't put nothing if you don't know it please

Mathematics
1 answer:
zhenek [66]3 years ago
5 0

Answer:

#2 - yes, no, yes, no

#4 - exponential

#5 - (y = 2x + 3) is linear, (y = 2x^3) is not linear, (y = 3x^2) is not linear, and (y = -x - 1) is linear

#6 - the last option

#7 - true, false, true, false

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The perimeter of a standard-sized rectangular rug is 36 is 36 ft. the length is 2 ft longer than the width. find the dimensions
evablogger [386]
The formula for the perimeter of a rectangle is P = 2L + 2W, where L is the length and W is the width. Because we don't know either the length or the width we can't solve the problem...too many unknowns.  BUT we do have some information that will help with this problem.  We are told that the length is 2 feet longer than the width, so we can use that: L = W+2.  Now we can make the substitution into the formula along with the value for the perimeter that was given to us: 36=2(W+2) + 2W, and 36 = 2W + 4 + 2W; 36 = 4W + 4; 32 = 4W and W = 8.  Now go back to where you said that the length is 2 feet longer than the width.  If the width is 8, then 8+2 = 10 for the length.
4 0
3 years ago
Mrs. Galicia launched a rocket into the air from the top of a building. Answer the following questions based on the graph below:
marusya05 [52]

Answer:

The first blank is 20 and the second one is 1.25

Step-by-step explanation:

i just took the quiz

3 0
3 years ago
ALGEBRA NATION!!! NEED HELP :(
Vilka [71]
Length of AC is 5 I hope this helps I can’t think right right now so bare with me











6 0
3 years ago
Una piscina rectangular de 15 metros de largo por 9 metros de ancho està rodeada por un
stira [4]

Answer: 2 meters.

Step-by-step explanation:

Let w = width of the cement path.

Dimensions of pool : Length = 15 meters , width = 9 meters

Area of pool = length x width = 15 x 9 = 135 square meters

Along width cement path, the length of region = 2w+15

width = 2w+9

Area of road with pool =  (2w+15) (2w+9)

= 4w^2+30w+18w+135\\\\=4w^2+48w+135

Area of road = (Area of road with pool ) -(area of pool)

\Rightarrow\ 112 =4w^2+48w+135- 135\\\\\Rightarrow\ 112= 4w^2+48w\\\\\Rightarrow\ 4 w^2+48w-112=0\\\\\Rightarrow\ w^2+12w-28=0\ \ \ [\text{Divide both sides by 4}]\\\\\Rightarrow\ w^2+14w-2w-28=0\\\\\Rightarrow\ w(w+14)-2(w+14)=0\\\\\Rightarrow\ (w+14)(w-2)=0\\\\\Rightarrow\  w=-14\ or \ w=2

width cannot be negative, so w=2 meters

Hence, the width of the road = 2 meters.

8 0
3 years ago
If every student in a large Statistics class selects peanut M&M’s at random until they get a red candy, on average how many
kotykmax [81]

Question:

According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select peanut M&M's from an extra-large bag looking for a red candy.

If every student in a large Statistics class selects peanut M&M’s at random until they get a red candy, on average how many M&M’s will the students need to select? (Round your answer to two decimal places.).

Answer:

If every student in the large Statistics class selects peanut M&M’s at random until they get a red candy the expected value of the number of  M&M’s the students need to select is 8.33 M&M's.

Step-by-step explanation:

To solve the question, we note that the statistical data presents a geometric mean. That is the probability of success is of the form.

The amount of repeated Bernoulli trials required before n eventual success outcome or

The probability of having a given number of failures before the first success is recorded.

In geometric distribution, the probability of having an eventual successful outcome depends on the the completion of a certain number of attempts with each having the same probability of success.

If the probability of each of the preceding trials is p and the kth trial is the  first successful trial, then the probability of having k is given by

Pr(X=k) = (1-p)^{k-1}p  

The number of expected independent trials to arrive at the first success for a variable Xis 1/p where p is the expected success of each trial hence p is the probability for the red and the expected value of the number of trials is 1/p or where p = 12 % which is 0.12

1/p = 1/0.12 or 25/3 or 8.33.

4 0
3 years ago
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