Take into account, that in general, a cosine function of amplitude A, period T and vertical translation b, can be written as follow:
In the given case, you have:
A = 4
T = 3π/4
b = -3
By replacing you obtain:
Hence, the answer is:
f(x) = 4cos(8/3 x) - 3
Answer:
76.8
Step-by-step explanation:
1. We assume, that the number 31.25 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 100% equals 31.25, so we can write it down as 100%=31.25.
4. We know, that x% equals 24 of the output value, so we can write it down as x%=24.
5. Now we have two simple equations:
1) 100%=31.25
2) x%=24
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
100%/x%=31.25/24
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for 24 is what percent of 31.25
100%/x%=31.25/24
(100/x)*x=(31.25/24)*x - we multiply both sides of the equation by x
100=1.3020833333333*x - we divide both sides of the equation by (1.3020833333333) to get x
100/1.3020833333333=x
76.8=x
x=76.8
now we have:
24 is 76.8% of 31.25
Answer:
42gtt/m
Step-by-step explanation:
According to the scenario, computation of the given data are as follows,
Flow rate in gtt/min = (Total fluid in ml × Drop factor) ÷ (Total hours × 60)
Where, Total fluid in ml = 2,000ml
Drop factor = 15gtt/m
Total hours = 12hours
By putting the following value in the formula, we get
Flow rate in gtt/min = (2,000 × 15) ÷ (12 × 60)
= 30,000 ÷ 720
= 41.67 or 42gtt/m
The answer would be 5*C or 5C or 5(C) they all mean the same exact thing but if Kevin has 5 times as much no matter what billy has you’ll have to multiply that by 5 to see how much Kevin’s has so if billy has c then you multiply that by 5
