Answer:
Large surface area: To increase the light harvesting.
Leaf arrangement: To increase the absorption of sunlight.
Cuticle and upper epidermis: The presence of cuticle prevents the loss of water. ...
Numerous stomata: They allows more carbon dioxide to diffuse for photosynthesis
The answer is d im trying to write as long as possible so i exceed the 20 character minimum limit so yea<span>
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PLATO USERS
Intertidal Zone 10 m (33 ft)
Sublittoral Zone 200 m (660 ft)
Hadal Zone 10,911 m (35,797 ft)
Bathyal Zone 6,000 m (19,686 ft)
[ a ] the sublittoral zone or the shallowest bathyal zone
[ b ] the intertidal zone or the deepest hadal zone
[ c ] the oceanic zone or the deepest intertidal zone
[ d ] <em><u>"The Intertidal Zone Or The Shallowest Sublittoral Zone."</u></em>
Answer:
volume = 0.285 L
Explanation:
Henry constant is given as
![Henry constant = \frac{C}{P}](https://tex.z-dn.net/?f=Henry%20constant%20%20%3D%20%20%5Cfrac%7BC%7D%7BP%7D)
Where C is concentration
P is atmospheric pressure
![Henry\ constant = \frac{0.00056}{0.80} = 0.0007 M/atm](https://tex.z-dn.net/?f=Henry%5C%20constant%20%3D%20%5Cfrac%7B0.00056%7D%7B0.80%7D%20%3D%200.0007%20M%2Fatm)
when atmospheric pressure 4 atm
![solubility = K_H\times P](https://tex.z-dn.net/?f=solubility%20%3D%20K_H%5Ctimes%20P)
![= 0.0007 \times 4 = 0.0028 M](https://tex.z-dn.net/?f=%20%3D%200.0007%20%5Ctimes%204%20%3D%200.0028%20M)
In 5 litere blood , moles of N_2 ![= Molarity \times volume](https://tex.z-dn.net/?f=%20%3D%20Molarity%20%5Ctimes%20volume)
![= 0.0028 \times 5 = 0.014](https://tex.z-dn.net/?f=%3D%200.0028%20%5Ctimes%205%20%3D%200.014)
At surface moles ![= 0.0056 \times 5 = 0.0028](https://tex.z-dn.net/?f=%3D%200.0056%20%5Ctimes%205%20%3D%200.0028)
Moles of N_2 release = 0.014 - 0.0028 = 0.0112
Mass of ![N_2 = 0.0112 \times 28 = 0.314 g](https://tex.z-dn.net/?f=N_2%20%3D%200.0112%20%5Ctimes%2028%20%3D%200.314%20g)
T = 37 + 273 = 310 K
![VOLUME = \frac{nRT}{P}](https://tex.z-dn.net/?f=VOLUME%20%3D%20%5Cfrac%7BnRT%7D%7BP%7D)
![= \frac{0.0112\times 0.0821\times 310}{1}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B0.0112%5Ctimes%200.0821%5Ctimes%20310%7D%7B1%7D)
volume = 0.285 L