All categories

3 years ago

1/2x=13 help!!?????????

Mathematics

2 answers:

Dmitry_Shevchenko [17]3 years ago

7 0

First we do, 1/2*x=13÷1/2. Which gives us x=13 1/2. 13 1/2=26. Therefore, x=26. Hoped I helped. :)

motikmotik3 years ago

5 0

1/2 x 13 = 6.5 in decimal form
Fractions Form: 1 1/2

1/1 + 1/2

((1 × 2) + (1 × 1)) / (1 × 2)

(2 + 1) / 2

3/2

= 3/2

= 1 1/2

You might be interested in

Alegebraic Expressions and the order of operations

Butoxors [25]

Answer:

PEMDAS:

Parenthesis

Exponents

Multiplication(from left to right)

Division(from left to right)

Addition(from left to right)

Subtraction(from left to right)

Step-by-step explanation:

5 0

4 years ago

Are the following equations parallel, perpendicular, or neither?

m_a_m_a [10]

Answer:

neither one of them that solves the problem

7 0

2 years ago

When solving 389 : 6=, what is the remainder 4 5 6 2

kenny6666 [7]

The answer is 64 with a remainder of 5

6 0

3 years ago

Jess owns 4 red shirts, 5 blue shirts, and 3 white shirts. She chooses a shirt to wear at random. What is the probability that s

xxTIMURxx [149]

D is the answer because in total she has 12 shirts and 3 out of the twelve shirts are white. so find the percentage of 3/12 which i belive is 1/4

7 0

3 years ago

Find the solution of the following equation whose argument is strictly between 270^\circ270 ∘ 270, degree and 360^\circ360 ∘ 360

Natasha2012 [34]

$\rightarrow z^4=-625\\\\\rightarrow z=(-625+0i)^{\frac{1}{4}}\\\\\rightarrow x+iy=(-625+0i)^{\frac{1}{4}}\\\\ x=r \cos A\\\\y=r \sin A\\\\r \cos A=-625\\\\ r \sin A=0\\\\x^2+y^2=625^{2}\\\\r^2=625^{2}\\\\|r|=625\\\\ \tan A=\frac{0}{-625}\\\\ \tan A=0\\\\ A=\pi\\\\\rightarrow z= [625(\cos (2k \pi+pi) +i \sin (2k\pi+ \pi)]^{\frac{1}{4}}\\\\k=0,1,2,3,4,....\\\\\rightarrow z=(625)^{\frac{1}{4}}[\cos \frac{(2k \pi+pi)}{4} +i \sin \frac{(2k\pi+ \pi)}{4}]$

$\rightarrow z_{0}=(625)^{\frac{1}{4}}[\cos \frac{pi}{4} +i \sin \frac{\pi)}{4}]\\\\\rightarrow z_{1}=(625)^{\frac{1}{4}}[\cos \frac{3\pi}{4} +i \sin \frac{3\pi}{4}]\\\\ \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]\\\\ \rightarrow z_{3}=(625)^{\frac{1}{4}}[\cos \frac{7\pi}{4} +i \sin \frac{7\pi}{4}]$

Argument of Complex number

Z=x+iy , is given by

If, x>0, y>0, Angle lies in first Quadrant.

If, x<0, y>0, Angle lies in Second Quadrant.

If, x<0, y<0, Angle lies in third Quadrant.

If, x>0, y<0, Angle lies in fourth Quadrant.

We have to find those roots among four roots whose argument is between 270° and 360°.So, that root is

$\rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]$

5 0

3 years ago