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joja [24]
3 years ago
8

PLEASE HELP ASAP I WILL MARK BRAINLIEST IF THERE ARE MULTIPLE ANSWERS!!!!!

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
4 0

Answer:

Attached

Step-by-step explanation:

x+8≥9

x ≥ 9-8

x ≥ 1

picture one is two dimension and picture 2 is number line

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How many thirtieths in 400 sq ft
ozzi
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ok well we could find out by dividing 400 by 30.
400 / 30 = 13.333333
We Can Round That To 13
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Write as Exponential form:a.a.a.c.c.c.c.m.m.m
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A^3c^3m^3

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Find the length of the height of the right trapezoid shown below, if it has the greatest possible area and its perimeter is equa
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Answer:

The height of the right trapezoid is   \frac{6}{5+\sqrt{3}}\ units

Step-by-step explanation:

Let

x ----> the height of the right trapezoid in units

we know that

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P=AB+BC+CD+DH+HA

we have

P=6\ units

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substitute

6=x+x+CD+DH+x

6=3x+CD+DH -----> equation A

<em>In the right triangle CDH</em>

sin(30\°)=\frac{CH}{CD}

sin(30\°)=\frac{1}{2}

so

Remember  that CH=x

\frac{1}{2}=\frac{x}{CD}

CD=2x

tan(30\°)=\frac{CH}{DH}

tan(30\°)=\frac{\sqrt{3}}{3}

so

\frac{\sqrt{3}}{3}=\frac{x}{DH}

DH=x\sqrt{3}

substitute the values in the equation A

6=3x+CD+DH -----> equation A

CD=2x

DH=x\sqrt{3}

6=3x+2x+x\sqrt{3}

6=5x+x\sqrt{3}

6=x[5+\sqrt{3}]

x=\frac{6}{5+\sqrt{3}}\ units

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Answer:

13

Step-by-step explanation:

two negatives make a positive

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Answer:

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2x^2-20+1

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18-20+1

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