Answer:
Option (A)
Step-by-step explanation:
Given:
LM ≅ OP
MN ≅ PQ
∠M ≅ ∠P
To Prove:
ΔLMN ≅ ΔOQP
Statements Reasons
1). LM ≅ OP 1). Given
2). MN ≅ PQ 2). Given
3). ∠P ≅ ∠M 3). Given
4). ΔLNM ≅ ΔOQP 4). By the SAS postulate of congruence.
[Side - Angle - Side]
Therefore, Option (A) will be the answer.
Answer:
0.09375 tons
Step-by-step explanation:
In this problem, it is given that Samuel has 3/4 tons of mulch i.e. 0.75 tons of mulch.
Again it is given that Samuel has to spread equally this amount of mulch in 8 square yards of the plot.
Since the mulch is spread uniformly, then we can say that in each square yard of the plot (0.75/8) = 0.09375 tons of mulch is been spread.
Therefore, 0.09375 tons of mulch will be spread in each square yard. (Answer)
$0.56. 0.7/5=$0.14 $0.14 is the amount per minute. so then you would multiply $0.14 x 4= $ 0.56
Please like I’m begging you please
Answer:
L.H.S.
= (cos5a.sin2a-cos4a.sin3a)/ (sin5a.sin2a-cos4a.cos3a)
Multiply numerator and denominator by 2.
= 2(cos5a.sin2a - cos4a.sin3a) / 2(sin5a.sin2a - cos4a.cos3a)
= (2cos5a.sin2a - 2cos4a.sin3a)/
(2sin5a.sin2a - 2cos4a.cos3a) = [sin(5a+2a)-sin(5a-2a)-sin(4a+3a)
+sin(4a-3a)]/[cos(5a-2a)-cos(5a+2a)-sin(4a-3a) +cos(4a+3a)]
= (sina - sin3a)/(cso3a-cosa)
= (-2cos2a.sina)/(-2sin2a.sina)
= cos2a/sin2a
= cot2a
= R.H.S.
