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abruzzese [7]
3 years ago
8

Friday and you are leaving school . You are going to the pizza palace and then the movies with your friends . After the movies y

ou go home and Saturday you wake up to spend the day at the park and then go to the school to play on the basketball court. After a very active day you go home to sleep. Determine the total distance you traveled on Friday and Saturday if you always took the most direct route (HINT : Find the hypotenuse ). Each cell on the graph represents one mile. The total distance traveled will puzzle four ! Round all your answers to the nearest hundredth

Mathematics
1 answer:
alina1380 [7]3 years ago
6 0

Answer:

49

Step-by-step explanation:

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A football is thrown from the top of the stands, 50 feet above the ground at an initial velocity of 62 ft/sec and at an angle of
Anvisha [2.4K]

a. i. The parametric equation for the horizontal movement is x = 43.84t

ii. The parametric equation for the vertical movement is y = 50 + 43.84t

b. the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

<h2>a. Parametric equations</h2>

A parametric equation is an equation that defines a set of quantities a functions of one or more independent variables called parameters.

<h3>i. Parametric equation for the horizontal movement</h3>

The parametric equation for the horizontal movement is x = 43.84t

Since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the horizontal component of the velocity is v' = vcosФ.

So, the horizontal distance the football moves in time, t is x = vcosФt

= vtcosФ

= 62tcos45°

= 62t × 0.7071

= 43.84t

So, the parametric equation for the horizontal movement is x = 43.84t

<h3>ii Parametric equation for the vertical movement</h3>

The parametric equation for the vertical movement is y = 50 + 43.84t

Also, since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the vertical component of the velocity is v" = vsinФ.

Since the football is initially at a height of h = 50 feet, the vertical distance the football moves in time, t relative to the ground is y = 50 + vsinФt

= 50 + vtcosФ

= 50 + 62tsin45°

= 50 + 62t × 0.7071

= 50 + 43.84t

<h3>b. Location of football at maximum height relative to starting point</h3>

The location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Since the football reaches maximum height at t = 1.37 s

The x coordinate of its location at maximum height is gotten by substituting t = 1.37 into x = 48.84t

So, x = 43.84t

x = 43.84 × 1.37

x = 60.0608

x ≅ 60.1 ft

The y coordinate of the football's location at maximum height relative to the ground is y = 50 + 48.84t

The y coordinate of the football's location at maximum height relative to the starting point is y - 50 = 48.84t

So,  y - 50 = 48.84t

y - 50 = 43.84 × 1.37

y - 50 = 60.0608

y - 50 ≅ 60.1 ft

So, the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Learn ore about parametric equations here:

brainly.com/question/8674159

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1. A translation of function f is f1(x) = b(x – h). It is equivalent to
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4 will be the correct answer to your question
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If RG = 4X+12 and HI = 10x-15, then x =​
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T and g are the answer because you can’t do 10x and 15
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Which is the best simplification of (24 x 32) / (2 x 3)?
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(24*32)/(2*3)
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Y = -2x +7<br><br><br> y = 3/4x +3
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Making the two equations equal to each other
it gives a quadratic equation
i hope this helps


please mark as brainliest
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