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3 years ago

Small point give away! Hope you guys enjoy!

Mathematics

2 answers:

Lostsunrise [7]3 years ago

8 0

Answer:

Wow everyone is being so noice today is today some kind of special occassion?

marin [14]3 years ago

3 0

Thanks!!

Can you please mark me brainliest :)

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The sum of ages of a man and his wife is 81. The ratio of their ages is 5:4. Find the age of the younger person.

slamgirl [31]

Answer:

A 30 years jjjajajajwiwkwkwiwqakaaiai

3 0

3 years ago

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I WILL MA FIRST ANSWER BRANILIST The map shows the location of the houses of Dan, Joe, Lee, and the coordinates of the community

emmasim [6.3K]

Look at the coordinates. They are both negative. (-5,-1)

Let me plot all the coordinates so you can see:

Joe= (-3,4)

Dan= (1,4)

Roy= (2,-3)

Lee= (-3,-4)

The only person with coordinates that are both negative is Lee.

"C" is the answer. Lee.

I hope this helps!
~kaikers

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4 years ago

Find the median for the following set of numbers: 12, 15, 15, 16, 19, 21, 25

Hoochie [10]

The median is the number in the middle of the data set.

There are 7 numbers, so the 4th number is the median.

(Another method is to eliminate a number on each side until you get to the middle number)

<h2>Answer:</h2>

The median is 16.

I hope this helps :)

7 0

3 years ago

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Write a multiplication equation that corresponds to each division equation. 10 divided by 5, 4.5 divided by 3, 1/2 divided by 4

nika2105 [10]

Answer: 1: 2 x 5 = 10 2: 1.5 x 3 = 4.5 3: 0.125 x 4 = 1/4

Step-by-step explanation:

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3 years ago

The isosceles triangle below has height AQ of length 3 and base BC of length 2. A point P may be placed anywhere along the line

eduard

The question is missing parts. Here is the complete question.

The isosceles triangle below has height AQ of length 3 and base BC of length 2. A point P may be placed anywhere along the line segment AQ.

What is the minimum value of the sum of the lengths of AP, BP and CP?

Answer: The sum is 4.73.

Step-by-step explanation: Height of a triangle is a perpendicualr line linking a vertex and its opposite side.

Because triangle ABC is isosceles, point Q divides the base in 2 equal parts:

BQ = CQ = 1

Suppose QP = x

To calculate minimum value of the sum:

AP = AQ - QP

AP = 3 - x

Since triangles BQP and CQP are congruent and right triangles, use Pythagorean Theorem to figure out the value of BP and CP:

BP = CP = $\sqrt{BQ^{2}+PQ^{2}}$

BP = $\sqrt{1+x^{2}}$

Then, sum of AP, BP and CP is

$f(x)=3-x+2\sqrt{1+x^{2}}$

The minimum value is calculated using first derivative:

$f'=-1+\frac{2x}{\sqrt{x^{2}+1} }$

The value of x is limited: it can assume value of 0, when P=A and x=3, when P=Q. So, interval is [0,3].

x has value:

$-1+\frac{2x}{\sqrt{x^{2}+1} }=0$

$2x=\sqrt{x^{2}+1}$

$4x^{2}-x^{2}-1=0$

$3x^{2}=1$

x = ± $\frac{1}{\sqrt{3} }$

x can't assume negative value because is not in the interval:

x = $\frac{1}{\sqrt{3} }$

To find the minimum value of the sum, substitute x in the function above:

f( $\frac{1}{\sqrt{3} }$ )= $3-\frac{1}{\sqrt{3} } +2\sqrt{1+(\frac{1}{\sqrt{3} })^{2} }$

$f(\frac{1}{\sqrt{3}} )=3-\frac{1}{\sqrt{3}}+2(\sqrt{\frac{4}{3} } )$

$f(\frac{1}{\sqrt{3}} )=3-\frac{1}{\sqrt{3}} +\frac{4}{\sqrt{3}}$

$f(\frac{1}{\sqrt{3}} )=3+\frac{3}{\sqrt{3} }$

$f(\frac{1}{\sqrt{3}} )=4.73$

The minimum value of the sum of AP, BP and CP is 4.73.

7 0

3 years ago