What is the value of a in this function's equation? A. -1 B. 1 C. 2 D. -2

The desert temperature, H, oscillates daily between 30ºF at 4am and 70ºF at 4pm. Write a possible formula for H in terms of t, m

densk [106]

The find step is to find C which is the vertical shift. This is the average between the maximum and minimum. So its 30+70=100/2= 50. the amplitude (A) take the average of the difference between max. temp. and min. value So 70-30= 40/2= 20, but it becomes -20 because the graph is shifted up 50 degrees and decreases to 30 at 4a.m. Then the period is 2pi/B which is 2pi/24, which equals pi/12. A=-20 B= pi/12 C=50

5 0

3 years ago

Can someone please help me out? It would really make me happier if you did.

asambeis [7]

Answer:

B) 8 and 24.

Step-by-step explanation:

Just by looking at the answer choices, since one number must be three times the other, we can determine that the correct answer is B.

Regardless, let's work this out mathematically. Let the first number be a and the second number be b.

Their difference is 16. Hence:

$a-b=16$

The first number is three times the second number. So:

$a=3b$

Substitute:

$3b-b=16$

Solve for b. Subtract:

$2b=16$

And divide both sides by two:

$b=8$

So, the second number is 8.

And since the first number is three times the second, the first number is 24.

Our answer is B as expected.

5 0

3 years ago

Jenna is opening a clothing store. She plans to start by selling T-shirts. If it costs her $7 for each shirt, $2 for ink per shi

butalik [34]

Add every thing and u. Get 10.10 7x2 then 14. Then add 10 so u basically just in total get 14.10

5 0

3 years ago

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What is the probability that a randomly selected makeup item from her bag will be an eyeshadow, if she has 15 cosmetics and only

Lelu [443]

The answer is 5/15 which is simplified to 1/3

8 0

3 years ago

Csc^3x-csc^2x-cscx+1=cot^2x(cscx-1)

belka [17]

Verify the identity:

$csc^3x-csc^2x-cscx+1\qquad =cot^2x(cscx-1)\\\\csc^2x(cscx-1)-1(cscx-1) =\quad \downarrow\\\\(csc^2x-1)(cscx-1)\quad \qquad \ =\quad \downarrow\\\\\bigg(\dfrac{1}{sin^2x}-\dfrac{sin^2x}{sin^2x}\bigg)(cscx-1)\ =\quad \downarrow\\\\\\\bigg(\dfrac{1-sin^2x}{sin^2x}\bigg)(cscx-1)\qquad \ =\quad \downarrow\\\\\\\bigg(\dfrac{cos^2x}{sin^2x}\bigg)(cscx-1)\qquad \qquad =\quad \downarrow\\\\\\cot^2x(cscx-1)\qquad \qquad \qquad =cot^2x(cscx-1)\qquad \checkmark$

5 0

3 years ago

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